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satela [25.4K]
3 years ago
8

Both aerobic and anaerobic respiration yields a net gain of ATP molecules to be used as energy for living things. The process of

_________ would yield the highest number of ATP.
Biology
1 answer:
Shkiper50 [21]3 years ago
7 0
Aerobic respiration. Has a total of 36 ATP
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It appears that "hidden genetic variation" is responsible forallowing selection to move the average value of a traitbeyond the r
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Answer:

Selection may be defined as the process of selecting the more favorable species than the less favored one and can adapt in the environment. The selection increase the chances of survival of the organism.

The genetic variation hidden means the variation is not visible in the population and present in the form of heterozygotes in the population. This genetic variation can be expressed by the recombination of the heterozygotes in the population.

5 0
3 years ago
Duchenne muscular dystrophy is an X-linked recessive disease. A phenotypically normal couple wants to start a family. The woman’
Andreyy89

Answer:

\frac{1}{8}

Explanation:

From the question: Duchenne muscular dystrophy is an X-linked recessive disease.

Now for an X-linked recessive disorder to be affected by a male individual; it only requires the presence of only one copy of the recessive allele of the disease to be present BUT in a female individual. both copies of the recessive allele must be present.

Let the X-linked recessive disease(i.e Duchenne muscular dystrophy) be = (ⁿ)

However, we are told that the couples are normal and are unaffected. Therefore;

the male partner (XY) will be:   X^NY

the female partner (XY) will be: X^NX^N

Similarly, the question proceeds by telling us that: the woman's brother has the disease.

Definitely, it's possible that this unaffected woman is a carrier of the disease.

So, if she is a carrier; we have her traits to be: X^NX^n

NOW, if a cross exist between these couples; we have

X^NY     ×        X^NX^n

                     X^N                         Y

X^N                X^NX^N                  X^NY

X^n                 X^NX^n                   X^nY

So, we have offspring as follows:

X^NX^N  = normal unaffected female  

X^NY     = normal unaffected male

X^NX^n   = female carrier for the Duchenne muscular dystrophy disease

X^nY      = affected male with the Duchenne muscular dystrophy disease

So, the probability of the child to be affected with the disease = \frac{1}{4}

Also, the probability that the first child will be a male or a female = \frac{1}{2}

∴

the  probability that the couple’s first child will be affected = \frac{1}{4}*\frac{1}{2}

=\frac{1}{8}

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1.What is unique about the reflex behavior?
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In living things hydrolysis reactions result in formation of
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Explanation:

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