Answer:
A1) 125
A2) 47.5%
B) 30
Step-by-step explanation:
Remember 'of' in this sentence means times(*). % shows a certain number/100.
a1) 48% 'of' what number is 60?
(let unknown number be x)
48/100 *x=60
Solve the equation, and the answer is x=125
a2) what percentage 'of' 120 is 57?
(let the unknown percentage be x)
(x/100)*120=57
x=47.5%
b) 24 students= 80% of the total number of students
1%=24/80
100% of the total number of students=30
So, there are total of 30 students
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
</span></span></span></span>
<span>Cone Volume = (3.14 * 1.5^2 * 4.5) / 3
</span>Cone Volume = <span><span><span>10.5975
</span>
</span>
</span>
<span>
answer is B
</span>
Answer: Choice C
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
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Explanation:
Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.
Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.
Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.
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In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.
Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.
Answer:
36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.
This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.
X = 81



has a pvalue of 0.6844
X = 69



has a pvalue of 0.3156
0.6844 - 0.3156 = 0.3688
36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.
Answer:
11.67
Step-by-step explanation:
Given: Employee earn $175 for 15 hours
We know, the constant of variation means the rate of change.
To know The constant of variation, we need to find how much employee earn each hour.
∴ Constant of variation= 
Constant of variation= 
∴ Constant of variation= 11.67. (rounding off)