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Nat2105 [25]
3 years ago
11

I have no idea how to answer this question I've tried everything look at the Picture ​

Mathematics
1 answer:
zlopas [31]3 years ago
8 0

<u>Answer:</u>

a. the error is that he wrote 0.05 instead of 0.2

0.148835 ≈ 0.2

b.

0.2 = 2 × 0.1

0.2 = 2 × 10⁻¹

The mass is about 2 × 10⁻¹ kg

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Abe real estate is developing 15 solar homes per states. If the cost of each home is estimated at 80,000 what’s the projected co
Soloha48 [4]

Answer:

the Total cost= 1,200,000*number of states

Step-by-step explanation:

Given the  cost of each home is $80,000

The number of homes per state are 15

The Total cost of the project is = (Total number of houses per state) * (cost of each house) * (the number of states).

Therefore the total cost =15*80000*Number of states.=1,200,000*number of states

3 0
4 years ago
Check all solutions to the equation. x² =-4
vovangra [49]

Answer:

x=2i, -2i

Step-by-step explanation:

4 0
3 years ago
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If the volume of a cube is 1728cm^3 find its length of its side​
Shalnov [3]

Answer:

it's a very easy one and it's answer is 1728

7 0
3 years ago
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F(x) = -x^2+10x-6<br> Find f(-5)
lianna [129]

9514 1404 393

Answer:

  f(-5) = -81

Step-by-step explanation:

Put -5 where x is and do the arithmetic.

  f(-5) = -(-5)^2 +10(-5) -6

  f(-5) = -25 -50 -6

  f(-5) = -81

8 0
3 years ago
Find the measures of center for following. Data Frequency 30 - 34 1 35 - 39 0 40 - 44 3 45 - 49 7 50 - 54 5 55 - 59 10 60 - 64 1
dalvyx [7]

Answer: the mode is 67.2

Step-by-step explanation:

Given that;

Data               Frequency

30 - 34                 1

35 - 39                0

40 - 44                3

45 - 49                7

50 - 54                5

55 - 59               10

60 - 64               10

65 - 69              21

70 - 74               12

Mode = ?

we know that mode is the number that has the highest number of appearance of frequency, so in this case, the data group that has the highest frequency (21) is 65 - 69  

Lower class boundary of the modal group; L = 65

Frequency of the group before the modal group; Fm-1 = 10

Frequency of the modal group; Fm = 21

Frequency of the group after the modal group; Fm+1 = 12

Group width; G = 4

Now using the formula

Mode = L + [ (Fm - Fm-1) / ( (Fm - Fm-1) + (Fm - Fm+1) ) ] × W

so we substitute

Mode = 65 + [ (21 - 10) / ( (21 - 10) + (21 - 12) ) ] × 4

= 65 + [ 11 / 20] × 4

= 65 + 2.2

= 67.2    

Therefore the mode is 67.2

3 0
3 years ago
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