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2 years ago

Find the number of outcomes in the complement of the given event. Out of 246 shoes in a department store, 198 are women's shoes.

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

8 0

Answer:

I suppose that the event here is selecting randomly a shoe.

We know that there are 246 shoes in the store, and 198 of them are women's shoes.

Then there are 246 - 198 = 48 shoes that are not women's shoes.

This means that if the event is something like "finding randomly a women's shoe"

The complement would be "selecting randomly a shoe which is not a women's shoe"

And there will be 48 outcomes that meet this condition.

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Does this model represent a compound? Explain your<br> answer

zvonat [6]

Answer:

Step-by-step explanation:

The model shows two similar elements.

Although we do not know what the element is, we can conclude that the model is not a compound.

This is because the definition of a compound is when two different elements join.

However, the model has two similar elements, which forms a molecule, not a compound.

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2 years ago

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Solve for x help me pls

Maksim231197 [3]

Solve it separately
$5x-29 \ \textgreater \ -34
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add 29 to both sides then divide by 5
$x\ \textgreater \ -1$
for the second part
$2x+31\ \textless \ 29$
subtract 31 from both sides then divide by two
$x\ \textless \ -1$
which means the final answer is A
$x\ \textless \ -1 \\ or \\ x\ \textgreater \ -1$

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3 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$