Equation of a parabola is written in the form of f(x)=ax²+bx+c.
The equation passes through points (4,0), (1.2,0) and (0,12), therefore;
replacing the points in the equation y = ax² +bx+c
we get 0 = a(4)²+b(4) +c for (4,0)
0 = a (1.2)²+ b(1.2) +c for (1.2,0)
12 = a(0)² +b(0) +c for (0,12)
simplifying the equations we get
16a + 4b + c = 0
1.44a +1.2b + c = 0
+c = 12
thus the first two equations will be
16a + 4b = -12
1.44 a + 1.2b = -12 solving simultaneously
the value of a = 5/2 and b =-13
Thus, the equation of the parabola will be given by;
y= 5/2x² - 13x + 12 or y = 2.5x² - 13x + 12
Well a stadium should have benches a field a food stand bathrooms a hotbox and a building within it
Answer:
Statement: Triangle ACD is congruent to Triangle BCD
Reason: SSA (Side, Side, Angle)
The relationship is linear.
The reason why is because each time x increases by 1, the value of y increases by 3. In other words, the slope is 3 and it is constant no matter what two points you pick
x = input
y = output
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Extra Info:
slope = rise/run
slope = (change in y)/(change in x)
slope = 3/1
slope = 3
The y intercept is (0,6). Think backwards in terms of the pattern going on.
Or you can plug m = 3 and (x,y) = (1,9) into y = mx+b and solve for b to get b = 6
1. To solve this problem, you need to remember that an exponential function has the following form:
f(x)=a^x
"a" is the base and "x" is the exponent.
2. It is important to know that the logarithmic functions and the exponential functionsare inverse. Then, you have:
<span>y=ln x
</span> e^y=e^(lnx)
<span> e^y=x
3. Therefore, the answer is:
</span>
x=<span>e^y</span>
