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diamong [38]
4 years ago
12

How do you write 75% as a fraction, mixed number, or whole number in simplest form?

Mathematics
2 answers:
Rina8888 [55]4 years ago
7 0

The answer is 3/4. Have a great day!

ololo11 [35]4 years ago
4 0
As a fraction  75%  = 75/100 = 3/4  (  by dividing top and bottom by 25)
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What is 85.87 rounded to the nearest whole number?
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The answer is D, because you move to the right of the decimal to see if that number is 5 or above. Then you round up, (to 86). :) Hope this was helpful.
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How many solutions is in 8x=0
torisob [31]

Answer:

0

Step-by-step explanation:

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3 years ago
Independent Practice
Maru [420]

Answer: THE ANSWER IS D. Yes; no value in the domain corresponds to more than one value in the range.

Find the domain and range.

Domain:

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Range:

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Step-by-step explanation: ITS NOT A OR C

Determine if the relation is a function.

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5 0
3 years ago
A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =
AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have \mu = 43, \sigma = 4

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 43}{4}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

4 0
3 years ago
CAN SOMEONE HELP WITH THE STEPS THXX
ss7ja [257]
4 for #1
1.3 for #2
Rate this 5 stars please
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3 years ago
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