<h3>
Answer: 1</h3>
where x is nonzero
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Explanation:
We'll use two rules here
- (a^b)^c = a^(b*c) ... multiply exponents
- a^b*a^c = a^(b+c) ... add exponents
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The portion [ x^(a-b) ]^(a+b) would turn into x^[ (a-b)(a+b) ] after using the first rule shown above. That turns into x^(a^2 - b^2) after using the difference of squares rule.
Similarly, the second portion turns into x^(b^2-c^2) and the third part becomes x^(c^2-a^2)
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After applying rule 1 to each of the three pieces, we will have 3 bases of x with the exponents of (a^2-b^2), (b^2-c^2) and (c^2-a^2)
Add up those exponents (using rule 2 above) and we get
(a^2-b^2)+(b^2-c^2)+(c^2-a^2)
a^2-b^2+b^2-c^2+c^2-a^2
(a^2-a^2) + (-b^2+b^2) + (-c^2+c^2)
0a^2 + 0b^2 + 0c^2
0+0+0
0
All three exponents add to 0. As long as x is nonzero, then x^0 = 1
Answer:
A
Step-by-step explanation:
plug in y and x, if you want to be sure of each answer
In the case of A) here are the 2 equations, y-2=x+4 and 3x+4=x+6
now plug in what a describes
x=1, y=7
7-2=1+4 and 7=7
Therefore the answer is A
Answer:
2
Step-by-step explanation:
4 dvided by 2 is 2
10 didide by 2 is 5
9,11,13,20
20 -9 = 11
Range: 11 so its not 17
11 + 13 = 24
24/2 = 12
Median: 12 so its not 10
9+ 11 + 13 + 20 = 53
53/4= 13.25
Mean: 13.25 so its not 12
IQR: 6.5 so its not 7 or 12
10 of them fail so 10 of them get 0 and no points to there GPA
