The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
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24 is what i believe the answer is
10.) x+25=30
x=5
11.) 60=3x-12
72=3x
x=72/3
x=24
12.) <1+<2=90
<1+17=90
<1=90-17
m <1=73 degrees
13.) m <3+m <4=180
46+m <4=180
180-46=m<4
134=m<4
Y=Ф + 8/(ФcosФ) ==> note that
dy/dФ = 1 - 8/[(ФcosФ)]² x (-8sinФ) ==> dy/dФ = 1+[(64sinФ)/Фcos²Ф]
==> dy/dФ = 1+ 64tanФ/Ф or dy/dФ = (Ф+tanФ)/Ф
To find the number between each tick, subtract the range from the number of spaces in between, so 5000/5=1000. D would therefore be at 4000. Add 300 to that to get Sophia's score, 7000. This should be marked two ticks after where 500 is marked
