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3 years ago

13

Helppppppppppppp!!!!!! helppppppppppppppp

1 answer:

sattari [20]3 years ago

8 0

Answer:

im blind

Step-by-step explanation:

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PLEASE HELP ME!!!!!!

Sonja [21]

Answer:

$\huge \red{ c_3 = - 1}$

Step-by-step explanation:

$c_1 = 1 \\ \\ c_n= - 2c_{n-1}+5 \\ \\ c_2 = - 2c_{2-1}+5 \\ \\ c_2 = - 2c_{1}+5 \\ \\ c_2 = - 2(1)+5 \\ \\ c_2 = - 2+5 \\ \\ \huge \purple{c_2 =3} \\ \\ c_3 = - 2c_{3-1}+5 \\ \\ c_3 = - 2c_{2}+5 \\ \\ c_3 = - 2(3)+5 \\ \\ c_3= - 6+5 \\ \\ \huge \red{ c_3 = - 1}$

6 0

3 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

3 years ago

A town has a population of 5000 and grows at 4% every year. To the nearest year, how long will it be until the population will r

Rus_ich [418]

Answer:

About 21.457 years

Step-by-step explanation:

You can solve this by setting up a simple equation.

$5000\cdot 1.04^x \geq 11600$

$1.04^x \geq 2.32$

log base 1.04 2.32=x

$x\approx 21.457$ years

Hope this helps!

8 0

3 years ago

Molly bought two cabbages for 1.80 how many cabbages could she buy with 28.80

Alika [10]

She can buy 16 cabbages .

3 0

3 years ago

In a class of 35 students, 14 are male. what percent of the class is male?

mars1129 [50]

Total number of students = 35

Number of male students = 14

% of students that are male = $\frac{14}{35} * 100 = \frac{14}{7} * 20 = 2 * 20$ = 40 %

8 0

4 years ago