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sveticcg [70]
3 years ago
11

Find the equation of the line that passes through the point (6,-2) and has a slope of 1/2

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

y=1/2x-5

Step-by-step explanation:

m=1/2

y=1/2x+b

Plug (6,-2) into equation and solve for b

-2=6(1/2)+b

-2=3+b

-5=b

y=1/2x-5

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A force of 720 newtons stretches a spring 3 meters. A mass of 60 kilograms is attached to the end of the spring and is initially
Darina [25.2K]

Answer:

7.6

Step-by-step explanation:

6 0
3 years ago
Which is the result when the equation y = -2/5x + 5/2 is converted to<br> standard form?
mixer [17]

Answer:

 4x+10y-25=0

Step-by-step explanation:

y=-\frac{2}{5} x+\frac{5}{2}

Multiply by 10 on both sides,

10y=-4x+25\\

so 4x+10y-25=0

4 0
2 years ago
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How do you write algebraic expressions to model quantities?
katovenus [111]
To write algebraic expressions to model quantities is you base the algebraic expressions or mathematical values declared in words by the manner of how the sentence illustrates the said problem. For example, one minus a number is the difference of zero shall be
1. 1 – n = 0.
Other same examples, John bought 25 apples while Julia bought only 15 from the market. If Niccole bought twice as much as Julia’s, how many was Niccole’s apples? <span><span>
1.      </span>You state the problem by the sequence of the said problem and understanding the possible structure.</span> <span><span>
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Hence, 2Julia = 2(15) = 30 apples.


6 0
3 years ago
n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t
givi [52]

Answer:

\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}

We use this equation to find the value of r.

In this problem, we have that:

K = 16, P_{0} = 2, P(50) = 4

So we find the value of r.

P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}

4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}

4 = \frac{32e^{50r}}{14 + 2e^{50r}}

56 + 8e^{50r} = 32e^{50r}}

24e^{50r} = 56

e^{50r} = 2.33

Applying ln to both sides of the equality

50r = 0.8459

r = 0.017

So

The differential equation is

\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})

3 0
3 years ago
(-1)(-1)(-1)(-5)= <br> HELP PLZ
laila [671]

Answer: 5

Step-by-step explanation:

(-1)(-1)(-1)(-5)=

(-1)(-5)=5

5 0
3 years ago
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