Answer:
Na₂SO₄•(H₂O)₆.
Explanation:
<em>The mass that is lost when the sample is heated is water.</em>
Let's assume we have 100 g of the hydrate:
43 grams would be water (H₂O), while the rest (100-43=57) would be sodium sulfate anhydrous (Na₂SO₄).
We <u>convert both those masses to moles</u>, using their <em>respective molar masses</em>:
- H₂O ⇒ 43 g ÷ 18 g/mol = 2.39 mol
- Na₂SO₄ ⇒ 57 g ÷ 142.04 g/mol = 0.40 mol
We can write those results as (Na₂SO₄)₀.₄₀•(H₂O)₂.₃₉. Now we just need<u> to multiply those numbers so that they become integers.</u>
If we multiply both coefficients by 5 we're left with (Na₂SO₄)₂•(H₂O)₁₂.
<u>Simplify </u>and thus the final answer is Na₂SO₄•(H₂O)₆.