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BigorU [14]
2 years ago
6

2)

Mathematics
1 answer:
Ahat [919]2 years ago
5 0
D /////////////////////////////
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How much would she have eaten after eight weeks?
Kamila [148]

Answer:

4 packages of gum in 8 weeks

Step-by-step explanation:

1/2 each week

1/2 x 8 = 4

7 0
2 years ago
10 day moving average
Lana71 [14]
That is 36.05

If it was wrong I’m Sorry
4 0
2 years ago
У = 3х +5<br> y = 8х +3<br> What’s the ordered pair answer in decimal form?
ludmilkaskok [199]

Answer:

(0.4,6.2)

Step-by-step explanation:

set the equations equal, 3x+5=8x+3

solve for x, 5x=2, x=2/5 = 0.4

plug in x value to solve for y, y = 3*0.4 + 5, y=6.2

5 0
3 years ago
Find the distance between -2 1/4 and 1 1/2​
liubo4ka [24]
The distance between would be 3 3/4.

First, you need to get out of the negatives.

-2 1/4+ 2 1/4= 0

2 1/4+ 1 1/2= 3 3/4

I’m sorry i this isn’t what your looking for :/
4 0
2 years ago
the company also discovered that it costs 30 to 2 widgets, 118 to produce 4 and 766 to produce 10 widgets. Find the total cost o
miv72 [106K]

We will first write cost function. As we are given three points here so we will use them to write quadratic function

y = ax^{2} +bx+c----------------------------------------(1)

So we will plug point (2,30) in it first ( for 2 widgets cost is 30)

So simply plug 30 in y place and 2 in x place in equation (1) as shown

30 = a(2)^{2} +b(2)+c

30 = 4a +2b +c ----------------------------------------------(2)

Similarly plug next point (4,118) now in equation (1)

118 = a(4)^{2} +b(4)+c

118 = 16a +4b +c ----------------------------------------------(3)

Similarly plug third point (10,766) now in equation (1)

766 = a(10)^{2} +b(10)+c

766 = 100a +10b +c ----------------------------------------------(4)

Now we have to solve system of linear equations (2),(3) and (4) for a,b,c

We can use method of elimination

Subtract equation (3) - equation (2)

118 = 16a +4b +c

-(30 = 4a +2b +c)

----------------------------------------------------

88 = 12a +2b -----------------------------------(5)

Similarly subtract equation (4)-equation (3)

766 =100a +10b +c

-( 118 = 16a +4b +c)

--------------------------------------

648 = 84a + 6b ------------------------(6)

Now to eliminate b in equations (5) and (6) multiply equation (5) by -3 and then add to equation (6)

-3×(88 = 12a +2b)

-264 = -36a - 6b

648 = 84a + 6b

---------------------------------

384 = 48a

Now solve for a

\frac{384}{48} = \frac{48a}{48}

8 = a

Plug 8 in a place in equation (5) or (6) and solve for b as shown

88 = 12(8) +2b

88 = 96 + 2b

88 -96 = 96 +2b -96

-8 = 2b

\frac{-8}{2} = \frac{2b}{2}

-4 = b

now plug 8 in a place, -4 in b place in either of equations (2),(3) or (4) and solve for c

30 = 4(8) +2(-4) +c

30 = 32 -8 + c

30 = 24 + c

30 - 24 = 24 + c - 24

6 = c

So plugging values of a as 8, b as -4 and c as 6 in equation (1) we get

y = 8x^{2} -4x+ 6

So thats the cost function. So now for 6 widgets, plug 6 in x place in this equation and find y value

y = 8(6)^{2} -4(6)+ 6

y = 8(36) - 24 +6

y = 288 -24 +6

y = 270

So $270 is the cost for producing 6 widgets and thats the final answer

4 0
3 years ago
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