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Sloan [31]
3 years ago
12

Solve the equation by taking square roots. Problem: 8b^2-7=-76

Mathematics
1 answer:
yulyashka [42]3 years ago
6 0

Answer:

b = +5

Step-by-step explanation:

8b^2=193+7

8b^2=200

b^2= 200/8

b^2=25

b=√25

b=+5

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I need help please :/
OleMash [197]

Part (a)

Plug in y = 0 and solve for x. Use the zero product property

y = x(x+3)(x-2)

0 = x(x+3)(x-2)

x(x+3)(x-2) = 0

x = 0 or x+3 = 0 or x-2 = 0 .... zero product property

x = 0 or x = -3 or x = 2

The three roots or zeros are x = 0 or x = -3 or x = 2

================================================

Part (b)

The roots of the graph are: x = -2, x = 1, x = 3. Each root is where the graph crosses or touches the horizontal x axis.

Note how x = 0 is found in part (a), but not found here. This is one example where the graphs don't match. Another would be x = -3 is in part (a), but not here.

So that's why the graph does <u>not</u> match with the function in part (a)

7 0
3 years ago
PLEASE HELP!!!<br><br> What is the solution set for 10 - 4x &lt; -22?
Tom [10]

Answer:

x > 8

Step-by-step explanation:

Solve for x to find the solution.

10 - 4x < -22

Subtract 10 from both sides.

-4x < -32

Divide both sides by -4. Flip the sign when dividing by negative.

x > 8.

7 0
2 years ago
Read 2 more answers
When solving a system of linear equations, when would you want to solve by graphing? When would you want to solve by substitutio
NARA [144]
It’s A bud I got this question before
5 0
3 years ago
Question 2
BabaBlast [244]

Answer:

The equation of the required line is y = x + 5

Step-by-step explanation:

The equation of the given line is y = x - 2

The required line = A line parallel to the given line

The point through which the required line passes = (-3, 2)

The general form of the equation of a straight line, is y = m·x + c

Where;

m = The slope of the line

By comparison, the slope of the given line, m = 1

When two lines are parallel, their slope are equal

Therefore, the slope of the required line = m = 1

The equation of the required line in point and slope form is therefore;

y - 2 = x - (-3) = x + 3

∴y = x + 3 + 2 = x + 5

The equation of the required line is therefore;

y = x + 5.

6 0
2 years ago
What is the square root of 289??
professor190 [17]

Answer:

square root of 289 is

<h2><em><u>1</u></em><em><u>7</u></em></h2>

Step-by-step explanation:

hope that will help you

6 0
3 years ago
Read 2 more answers
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