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solniwko [45]
3 years ago
9

5. a : 4, for a = 32

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

8

Step-by-step explanation:

put 4 in place for a

4=32

dive both sides by 4 and you will get 8

hope this helps

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Ahmad is choosing a password to access his teacher’s web page. He must choose a capital letter and three nonrepeating digits fro
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Answer:

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Step-by-step explanation:

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2 years ago
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Mrs.Davis bought 6 pounds of grapes for 18 dallors at this rate how much would 72 ounces of grapes have cost
harkovskaia [24]

Answer:

Cost of 72 ounces of grapes is $13.5


Step-by-step explanation:

In order to solve his problem, we first need to get all the values in the same units.

  1 pound = 16 ounces

∴ 6 pounds= 16×6 = 96 ounces

Now by unitary method, we solve the question as follows:

price of 96 ounces of grapes = $ 18

price of 1 ounce of grapes = $ (18÷96)

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4 0
3 years ago
I need helppp!!! <br> −50=10s
Nimfa-mama [501]
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4 0
3 years ago
Alex wants to sew a pillow in the shape below. How many square yards of fabric are needed to sew the pillow? Fabric is only sold
r-ruslan [8.4K]

The shape is missing, so i have attached it.

Answer:

2.6

Step-by-step explanation:

From the image attached, the diameter of the inner semi - circle is 0.5 yards while the length of each side of the pillow is 0.2 yards.

Thus, for us to find the length of the seam which is along the edges of the pillow, we will calculate the perimeter of the outer semicircle, then add the perimeter of the inner semicircle and also add the sides too.

Now, due to the fact that the length of the sides of the pillow are 0.2 yards each, the diameter of the outer circle would be;

0.5 + 0.2 + 0.2 = 0.9 yards. So, the perimeter of the outer semicircle is,

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The perimeter of the inner semicircle would be given as;

PI = πd/2 = π × 0.5/2 =0.25π yds.

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PT = P0 + PI + 0.2 + 0.2

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7 0
3 years ago
Given z1 = -3
trasher [3.6K]

Answer:

See explanation

Step-by-step explanation:

The given complex number are:

z_1=-3\sqrt{3}+3i

and

z_2=6\cos 150\degree+6i\sin 150\degree

When we rewrite z_1=-3\sqrt{3}+3i in complex form, we obtain;

z_1=r(\cos \theta+i\sin \theta)

where

r=\sqrt{(-3\sqrt{3})^2+3^2 }=\sqrt{36}=6

and

\theta=tan^{-1}(\frac{y}{x})

\implies \theta=tan^{-1}(\frac{-3\sqrt{3}}{3})=150\degree

Hence,

z_1=6(\cos 150\degree+i\sin 150\degree)

z_1=6\cos 150\degree+6i\sin 150\degree

Hence

z_1=z_2

8 0
3 years ago
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