To find scale factor you first must find two corresponding sides. then divide one by the other. note that if you divide the smaller side by the larger you will get a number less that one and if you divide the larger side by the smaller side you will get a number greater than one.
Answer: If it is probability, there is a 40% chance that a school will receive a defective calculator if the selections are random.
If the calculators are tested and sorted, there can be 3 selections of 4 calculators sent to schools once the 8 defective ones are removed.
Step-by-step explanation: The question is unclear. Is it about subtracting the bad ones and dividing the good ones? Or is it about Taking chances with the selection of calculators to be sent?
If they subtract: 20-8= 12 left 12÷4= 3 sets of good ones.
If they take chances 8/20 = .4 so there is a 40% chance that a bad calculator will be included in the selection.
This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.
There aren't any parallel lines involved in the above described construction, so I'll skip the first one.
2. Why do the circles have to be congruent ...
The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.
3. ... circles of different sizes ...
[We just answered that. Let's do it again.]
Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.
4. ... construct the perpendicular bisector ... a different way?
Maybe what I first described is different; there are no parallel lines.
Answer:
150 inches
Step-by-step explanation:
C=2πr
2·π·24 ≈ 150.79645