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3 years ago

You have the option of buying 20 tickets at the fair for 15$ or 45 for 27$ which is te best deal

Mathematics

2 answers:

GrogVix [38]3 years ago

7 0

Answer:

45 for 27

Step-by-step explanation:

0.6 for each ticket therefore cheaper

plzz give me brainliest

Lostsunrise [7]3 years ago

3 0

45 tickets for 27$is definitely the best deal because if you go with the first option and buy it twice you will pay 25$for only 40 I can’t Explain properly but definitely 45 for 26$

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Determine if "h=3" is a solution.<br> 3h=2(h+2)-1

lutik1710 [3]

Answer:

Yes is a solution

Step-by-step explanation:

3h = 2(h+2)-1

We replace h=3

3*3 = 2(3+2) - 1

Solve

9 = 2(5)-1

9 = 10 - 1

9 = 9

Is correct h= 3

when we manage to find the same value on both sides of equality it means that the value entered is a possible option

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Help!! Me with my aleks!

Mashcka [7]

Answer:

9x + 36 = 10

Step-by-step explanation:

Given

$\frac{3}{4}$ x + 3 = $\frac{5}{6}$

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3 years ago

Avi's pet hamster Chubby loves to run in his hamster wheel. During one "race", Avi counts 100 rotations of the wheel. She wants

Fantom [35]

Answer: 800pi inches

=======================================

Explanation:

The formula to find the circumference of a circle is
C = pi*d
where
C = distance around the circle (aka circumference)
pi = 3.14 approximately
d = diameter

We know that the diameter of the wheel is d = 8, so
C = pi*d
C = pi*8
C = 8pi
is the circumference of the wheel

One full rotation will have the wheel cover a distance of 8pi inches. Imagine that wet paint is on the outer surface of the wheel. If the wheel is rolled out in a straight line, then the wet paint would cover a linear distance of 8pi inches along the flat ground. This is one full rotation, so 100 rotations covers 100*8pi = 800pi inches

Note: if we use pi = 3.14 as the approximation, then the hamster ran approximately 800*pi = 800*3.14 = 2512 inches if the wheel could move

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3 years ago

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Sonja [21]

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Distance AB = $\sqrt{(8-0)^2+(8--7)^2}$
Distance AB = $\sqrt{8^2+15^2}$
Distance AB = $\sqrt{289}$
Distance AB = 17

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3 years ago

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erastova [34]

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