All categories

2 years ago

Help please. i need it asap!

Mathematics

1 answer:

garri49 [273]2 years ago

8 0

Answer:

$u = 8.27$

Step-by-step explanation:

$cross \: multi pling \: you \: have$

<h3>7×13=11U </h3><h3>making U subject of formula you have </h3><h3> 91= 11U </h3><h2>therefore U = 91/11= 8.97 </h2>

You might be interested in

A rectangle has an area of 20 square feet a similar rectangle has an area of 180 square feet what is ratio of the areas of these

Evgen [1.6K]

Answer:

The ratio of the areas of the smaller rectangle to the larger rectangle is $\frac{1}{9}$

Step-by-step explanation:

we know that

if two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z-----> the scale factor

x-----> the area of the smaller rectangle

y----> the area of the larger rectangle

$z^{2}=\frac{x}{y}$

substitute the values

$z^{2}=\frac{20}{180}$

simplify

$z^{2}=\frac{1}{9}$

That means, the area of the larger rectangle is 9 times the area of the smaller rectangle

$z=\frac{1}{3}$ ------> the scale factor

That means, the dimensions of the larger rectangle is 3 times the dimensions of the smaller rectangle

7 0

2 years ago

Is(5, 6)a solution to the inequality<br> y < 2x + 4 ?

Diano4ka-milaya [45]

Answer:

yes

Step-by-step explanation:

y < 2x +4

6 < 2·5 +4

6 < 14

4 0

2 years ago

Round 3,236 to the nearest hundred<br>

Xelga [282]

Answer:

3,200

Step-by-step explanation:

3 is less than 5 so you round down to 3,200

7 0

2 years ago

Read 2 more answers

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago

Please help me with math please, they are number lines

Novay_Z [31]

So u have to rearrange to find x again
You look at the equation and u can see that if u take away 14 from both sides it will leave u with:
X/-3<-2
Now as x is over - 3, the opposite of divide is multiply, so you multiply both sides by - 3.
This leaves you with your answer:
x<6

So the number line which represents this is C.

3 0

3 years ago