The given function is,

The graph can be drawn as,
The period will be distance between two consequetive maximas,

Thus, period is correct.
The amplitude can be determined as,

Thus, amplitue is incorrect.
The range is,

Thus, the range is correct.
The midline is,

Thus, the midline is correct.
Thus, option (b) is the solution.
Answer
18(2)+12(2)-4(5)
36+24-20
60-20
40
Step-by-step explanation:
since they had two-18 yard passes and two 12 yard runs, that's the first part of the expression, and then they had four penalties that cost them 5 yards, and that was the last term. When you simplify, you end up with 40 yards gained.
In math
Passes: 18(2)
Runs: 12(2)
Penalties:4(5)
equation
18(2)*12(2)-4(5)
Hope it helped
Answer:
68 hours
Step-by-step explanation:
Going by the time frame and date attached to this question, if school holidays should begin by Saturday 9 am, then from 1pm today we are 68 hours away from holiday.
The probability of choosing Joey first is 1/12 .
If that happens, the probability of choosing Chloe next is 1/11 .
Then, the probability of choosing Zoe after that is 1/10 .
The probability of all these things happening is
(1/12) x (1/11) x (1/10)
= 1/1320 = 0.00076 = 0.076 percent
Answer:
Use your brain
Step-by-step explanation: