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3 years ago

Explain the steps when solving for the variable y 12x+2y=18

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

Answer:

Step-by-step explanation:

First, you need to subtract both sides by 12x

12x+ 2y=18

-12x -12x

That will give you: 2y= 18-12x

Next, you need to deviede both sides by 2

2y/2= 18-12x/2

That gives you the answer:

y= 18-6x

(im not 100% sure but i think this is right, feel free to correct me)

makvit [3.9K]3 years ago

3 0

Answer:

Simplifying

12x + 2y = 18

Solving

12x + 2y = 18

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

12x + 2y + -2y = 18 + -2y

Combine like terms: 2y + -2y = 0

12x + 0 = 18 + -2y

12x = 18 + -2y

Divide each side by '12'.

x = 1.5 + -0.1666666667y

Simplifying

x = 1.5 + -0.1666666667y

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Helen [10]

$\frac{3}{5}$ × $4 \frac{1}{6}$

First, convert $4\frac{1}{6}$ to an improper fraction. Use this rule: $a \frac{b}{c}$ = $\frac{ac+b}{c}$ / Your problem should look like: $\frac{3}{5}$ × $\frac{4x6+1}{6}$
Second, simplify 4 × 6 to 24. / Your problem should look like: $\frac{3}{5}$ × $\frac{24+1}{6}$
Third, simplify 24 + 1 to 25. / Your problem should look like: $\frac{3}{5}$ × $\frac{25}{6}$
Fourth, apply this rule: $\frac{a}{b}$ × $\frac{c}{d}$ = $\frac{ac}{bd}$ / Your problem should look like: $\frac{3x25}{5x6}$
Fifth, simplify 3 × 25 to 75. / Your problem should look like: $\frac{75}{5x6}$
Sixth, simplify 5 × 6 to 30. / Your problem should look like: $\frac{75}{30}$
Seventh, simplify. / Your problem should look like: $\frac{5}{2}$
Eighth, convert to mixed fraction. / Your problem should look like: $2\frac{1}{2}$

Answer: $2 \frac{1}{2}$

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3 years ago

I need someone to answer this question

SIZIF [17.4K]

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2 years ago

An iceberg weighs 450,000 pounds if it loss 0.2% of its weight in a day, what is its new weight at the end of the day

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449 100

Step-by-step explanation:

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3 years ago

Read 2 more answers

Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

which is undefined when $x=-1$ , so this is the site of a vertical asymptote.

As $x$ gets arbitrarily large in magnitude, we find

$\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0$

since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

so there is one $y$ -intercept at (0, 1).

The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

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