$(1.18\cdot10^3)\cdot(9.1\cdot10^{-6})=(1.18\cdot9.1)(10^3\cdot10^{-6})\\\\=10.738\cdot10^{3+(-6)}=1.0738\cdot10\cdot10^{-3}\\\\=1.0738\cdot10^{1+(-3)}=1.0738\cdot10^{-2}\\\\Used:\\\\a^n\cdot a^m=a^{n+m}$

8 0

3 years ago

Two sets of the sum of a number and eight are added to five times the same number

olasank [31]

I found the answer to the same question you have.

5 0

3 years ago

What is the interquartile range of this box plot? And how do you find it?

Alik [6]

Answer:

Step-by-step explanation:

Calculate the median, which is the middle number of an ordered range with an odd number. 3.

Calculate the medians of the bottom and top halves, omitting the middle number. Since these are now even-numbered sets, we'll take the average of the middle two numbers of each. Lower is 1.5, upper is 4.5.

Calculate the difference of the upper median and lower median, so 4.5 - 1.5 = 3.

4 0

3 years ago