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Liula [17]
3 years ago
13

50% of what number is 11.7

Mathematics
1 answer:
shusha [124]3 years ago
4 0
Let, the number = x
x * 50% = 11.7
x * 0.5 = 11.7
x = 11.7 / 0.5
x = 23.4

In short, Your Answer would be 23.4

Hope this helps!
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The circumference of a circle is 47.1 and the diameter of the circle is 15. Which best represents the value of π? 47.1/15 7.54/7
Vlad1618 [11]

Answer: 47.1/15

Step-by-step explanation:

We define Circumference by C= pie X D[diameter]

Hence pie= C/ D= 47.1/15

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Direction:Determine between what two integers the following square root of a number is. Select the letter of your choice below.
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Answer:

jsa-ygso-fxk join girls

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Answer: I think

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3 0
3 years ago
15 points please help!! :)<br> Find the value of x.
andriy [413]

Answer:

Question 4: -11

Question 5: -7

Step-by-step explanation:

Four

Every triangle has 180 degrees.

So all three angles add to 180

<em><u>Equation</u></em>

60 + 80 + x + 51 = 180

<em><u>Solution</u></em>

Combine the like terms on the left. This is the first time I've seen x be a negative value. Almost all of the time it isn't, which should make you wonder.

191 + x = 180    

Subtract 191 from both sides.

191 - 191 + x = 180 - 191

x = - 11

Five

If a triangle is a right triangle and one of the angles is 45, then so is the other one.

<em><u>Proof</u></em>

a + 45 + 90 = 180         Combine like terms on the left

a + 135 = 180                Subtract 135 on both sides.

a + 135-135=180-135    Combine the like terms

a = 45

<em><u>Statement</u></em>

That means 52 + x = 45 and here is another negative answer. Subtract 52 from both sides

52 - 52 + x = 45 - 52    Combine like terms.

x  = - 7

6 0
3 years ago
Read 2 more answers
A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the
EastWind [94]

Answer:

a) \hat p=\frac{471}{1024}=0.460

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Data given and notation  

n=1024 represent the random sample taken    

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

\hat p=\frac{471}{1024}=0.460 estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering    

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

Part b

If we replace the values obtained we got:

0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429

0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491

The 99% confidence interval would be given by (0.429;0.491)

8 0
3 years ago
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