Igebra 1: CC 2015 > Chapter 1: Rewriting Equations and Formulas > Section Exercises 1.5 > Exercise 33
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Answer:
S(-2, -3)
Step-by-step explanation:
Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;
S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;
x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1
Substitute the values into the formula;
X = ax2+bx1/a+b
X = 3(-1)+1(-5)/3+1
X = -3-5/4
X = -8/4
X = -2
Similarly;
Y = ay2+by1/a+b
Y = 3(-5)+1(3)/3+1
Y = -15+3/4
Y = -12/4
Y = -3
Hence the coordinate of the point (X, Y) is (-2, -3)
