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3 years ago

How can the freezing of surface waters make the water that is left unfrozen denser

Biology

2 answers:

yKpoI14uk [10]3 years ago

7 0

Explanation:

When an aqueous solution freezes, the unfrozen solution becomes denser. That's because some of the water has been removed as ice. However, the solutes remain dissolved in a solution with a smaller liquid volume. The concentration of the solution increases, so the density increases.

agasfer [191]3 years ago

3 0

this is because water expands as it gets cold hence floating leaving the unfrozen water dense

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In pea plants, long stems are dominant to short stems, purple flowers are dominant to white, and round peas are dominant to wrin

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Assuming the genes are not linked nor interacting with each other, the expected number of long stemmed plants with purple flowers, producing wrinkled peas, L-P-rr, is 288.

<h3>Available data</h3>

long stems are dominant to short stems
purple flowers are dominant to white,
round peas are dominant to wrinkled

Each trait is determined by a single, different gene.

A heter0zyg0us plant is self-crossed
F1) 2,048 descendants

Let us name te alleles as follows

L ⇒ Long stem
l ⇒ Short stem
P ⇒ Purple flowers
p ⇒ white flowers
R ⇒ Round peas
r ⇒ wrinkled peas

Cross) heter0zyg0us plant is self-crossed

Parental) LlPpRr

Gametes) LPR, LPr, LpR, Lpr, lPR, lPr, lpR, lpr

Assuming that these genes are not linked nor interacting with each other, to make the calcs easier we will make crosses considering each gene separately.

Stems

Parental) Ll x Ll

F1) 1/4 LL, 2/4 Ll, 1/4 ll

3/4 long stem, 1/4 short stem

Flower color

Parental) Pp x Pp

F1) 1/4 PP, 2/4 Pp, 1/4 pp

3/4 purple flowers, 1/4 white flowers

Peas

Parental) Rr x Rr

F1) 1/4 RR, 2/4 Rr, 1/4 rr

3/4 round peas, 1/4 wrinkled peas

Now, we will get the proportion of individuals with long stems, purple flowers, producing wrinkled peas, L-P-rr

Note: The symbol - is representing either a dominant or a recessive allele.

From the crosses, we know that

3/4 are long stemmed,
3/4 have purple flowers, and
1/4 have wrinkled peas.

To get the proportion of individuals expressing all these traits together, we just need to multiply these values.

3/4 L- x 3/4 P- x 1/4 rr = 9/64 L-P-rr

Knowing that the total number of plants is 2,048 and that there are 64 possible gametes combinations from this cross, we will use the proportion 9/64 to get the number of plants with these traits.

64 ------------- 2,048 plants

9 -------------- X = (9 x 2048) / 64 = 288 plants.

We expect to find 288 long stemmed plants with purple flowers, producing wrinkled peas.

You will learn more about trihybrid crosses at

brainly.com/question/21942441

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