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Liula [17]
4 years ago
11

Anyone know this? Thanks!​

Mathematics
1 answer:
Elan Coil [88]4 years ago
3 0

Answer:

I'm sorry I learned this and I believe yes but I forget

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What is the equation of the line that passes through the point (-5, -4) and has a
Nikolay [14]

Answer:

             y + 4 = -³/₅(x + 5)      {the point-slope form of the equation }

             y = -³/₅x - 7               {the slope-intercept form of the equation}

             3x + 5y = - 35               {standard form of the equation}

Step-by-step explanation:

The point-slope form of equation is : y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through.

m = -³/₅

(-5, -4)    ⇒   x₀ = -5,  y₀ = -4

Therefore:

y - (-4) =  -³/₅(x - (-5))

y + 4 = -³/₅(x + 5)      ←  the point-slope form of the equation

y + 4 = -³/₅x - 3              {subtract 4 from both sides}

y = -³/₅x - 7               ←  the slope-intercept form of the equation

³/₅x + y = - 7                     {multiply both sides by 5}

3x + 5y = - 35               ←  standard form of the equation

5 0
3 years ago
This net will be folded to form a prism.
Grace [21]

Answer:

it is a and c and b and e and also and f

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The width of a rectangle is 12cm less than the length. the perimeter is 156cm. what is the width?
ser-zykov [4K]

Answer:

25526

Step-by-step explanation:

5-=6haj

7 0
3 years ago
Twenty identical looking packets of white power are such that 15 contain cocaine and 5 do not. Four packets were randomly select
xxMikexx [17]

Answer:

The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.

Step-by-step explanation:

Probabilities of selecting 4 packets with the ilegal substance:

(\frac{15}{4})\\= \frac{15!}{4!(15-4)!}

Combinassions possible= 1365

Probabilities of selecting 2 packets with white powder:

(\frac{5}{2})= \frac{5!}{2!(5-2)!}

Combinations possible= 10

Probabilities of selecting 6 packets from the totality of them:

(\frac{20}{6}) = \frac{20!}{6!(20-6)!}

Combinations possible= 38760

The probability of picking 4 with the substance and 2 with only white powder is:

\frac{(15ncr4)(5ncr2)}{(20ncr6)} = 0.3522

I hope this answer helps you.

6 0
3 years ago
California license plates used to consist of a system of a number then letter followed by a number then a letter and a number th
zhenek [66]

Answer:

for second and third letters, we again have 26 combinations available and thus 26×26×26=17576 combinations for letters. But digits are from 0 to 9 i.e. 10 combinations for each place and tolal 10×10=100 combinations. Hence for LLLDD , we have 1,757,600 combinations available for license plates.

Step-by-step explanation:

4 0
3 years ago
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