Anyone know this? Thanks!

Please help!

crimeas [40]

Answer:

The zeros are:

$x =4, x=2, x = 5$

The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

$h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)$

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

$0=\left(x-4\right)^2\left(x^2-7x+10\right)$

switch sides

$\left(x-4\right)^2\left(x^2-7x+10\right)=0$

as

$x^2-7x+\:10=\left(x-2\right)\left(x-5\right)$

so

$\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

$\mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

so

$x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x =4, x=2, x = 5$

Thus, the zeros are:

$x =4, x=2, x = 5$

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

The function has three distinct real zeros.

Hence, option (B) is true.

4 0

3 years ago

From 1960 to 1980 , the consumer price index (cpi) increased from 29.6 to 82.4. If a frozen chicken pie cost $0.28 in 1960 and t

mojhsa [17]

CPI in 1960 = 29.6

CPI in 1980 = 82.4

Growth (%) in CPI = $\frac{\text{CPI in 1980 - CPI in 1960}}{\text{CPI in 1960}}$ × 100

⇒ Growth (%) in CPI = $\frac{82.4-29.6}{29.6}$ × 100

⇒ Growth (%) in CPI = 178.3783.. %

⇒ Growth (%) in CPI = 178.4%

Now, we know that price of frozen chicken pie in 1960 = $0.28

Also, we know that over 1960 to 1980, frozen chicken pie price grew at the same rate as CPI

Hence, Price of Chicken Pie in 1980 = Price of Chicken Pie in 1960 × (1 + Growth in CPI)

⇒ Price of Chicken Pie in 1980 = 0.28 × (1 + 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + (0.28 × 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.49952

⇒ Price of Chicken Pie in 1980 = 0.28 + 0.50

⇒ Price of Chicken Pie in 1980 = $0.78

Hence, price of chicken pie in 1980 would be ~$0.78

8 0

3 years ago

Read 2 more answers

Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached b

Advocard [28]

The question is incomplete.

The complete question is

Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached by a real estate agent representing a client who would like to exchange a parcel of land in North Carolina for Kase’s Maryland property. Kase agrees to the exchange.

What is Kase’s realized gain or loss, recognized gain or loss, and basis in the North Carolina property in each of the following alternative scenarios? (Loss amounts should be indicated by a minus sign. Leave no answer blank. Enter zero if applicable.)

a. The transaction qualifies as a like-kind exchange and the fair market value of each property is $907,500.

b. The transaction qualifies as a like-kind exchange and the fair market value of each property is $199,000.

Answer:

A. Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

B. Realised loss ( 199000 - 217000) = 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

Step-by-step explanation:

A.

Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

Here , we find that Kase has realised gain of $ 690,500 but recognised gain of $ 0 . It is so because Kase did not receive any boot and the transaction is a like-kind exchange. Therefore, the adjusted basis in new property = $ 217,000 ( as no gain is recognised ).

B.

Realised loss ( 199000 - 217000 )= 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

7 0

3 years ago

10 POINTS + BRAINLIEST TO FIRST CORRECT ANSWER!!! THANK YOU!

Fofino [41]

Answer:

The answer is A (Look at the graph of the relationship. Find the y-value of the point that corresponds to x = 1. That value is the unit rate)

Step-by-step explanation:

Because the proportional relation is defined by k = $\frac{y}{x}$ . If ratio is $\frac{units}{1unit}$ then it is a rate. Unit rate means per 1 unit such as $\frac{amountofmoney}{1kg}$ or $\frac{km}{1hour}$ thus the correct answer is A.