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geniusboy [140]
3 years ago
6

Which set of goals can at times conflict in the short run

Business
1 answer:
kondor19780726 [428]3 years ago
7 0
Correct Answer : C; High employment and price level stability.
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1. Albacore Corporation purchased a new machine costing $27,600 on January 1, 2017. The machine is expected to have a $1,800 sal
docker41 [41]

Answer:

Annual depreciation= $4,300

Explanation:

Giving the following information:

Purchasing price= $27,600

Salvage value= $1,800

Useful life= 6 years

To calculate the depreciation expense using the straight-line method, we need the following formula:

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (27,600 - 1,800) / 6= $4,300

7 0
3 years ago
Caracteristicas de un seguro público
mr Goodwill [35]
It’s Spanish lol lol lol
6 0
3 years ago
Business fluctuations are systematic increases and decreases in real GDP. Please select the best answer from the choices provide
BlackZzzverrR [31]
From the subject of economics, specifically macroeconomics,  it says that the statement above is false. <span>Business cycles, not business fluctuations, are systematic increases and decreases in real GDP. Business fluctuations are called unsystematic changes. </span>
5 0
3 years ago
Read 2 more answers
Baker Corp. is required by a debt agreement to maintain a current ratio of at least​ 2.5, and​ Baker's current ratio now is 3. B
Orlov [11]

Answer:

$1.67 Million

Explanation:

Current asset = 15 Million    

Current liabiltiy = 15 Million/3

                          = 5 Million    

Let the inventory X can be purchased with short term debt without violation

per current ratio requirement    

(15 + x)/5+x = 2.5    

       15 + x  = 12.5 + 2.5x    

            2.5 = 1.5x    

               x = $1.67 Million

Therefore, $1.67 Million inventory can Baker purchase without violating its debt agreement if their total current assets equal​ $15 million

7 0
4 years ago
Write the AddressList method newBusiness. This method searches addresses for an existing business with an identical address (i.e
max2010maxim [7]

Answer:

See explaination

Explanation:

// Address.java

public class Address {

/**

* The name of the business

*/

private String name;

/**

* The name of the street the business is on

*/

private String street;

/**

* The street number of the business

*/

private int number;

/**

* Constructs an Address that represents a business with name nm,

* at number no on the street st

*/

public Address(String nm, String st, int no)

{

name = nm;

street = st;

number = no;

}

/**

* Returns the name of the business

*/

public String getName()

{

return name;

}

/**

* Returns the name of the street on which the business is located

*/

public String getStreet()

{

return street;

}

/**

* Returns the street number of the business

*/

public int getNumber()

{

return number;

}

}

//end of Address.java

//AddressBook.java

import java.util.ArrayList;

import java.util.List;

public class AddressBook {

/**

* The list of business addresses. No two businesses in the list

* can have the same address (both the same street and street number)

*/

private List<Address> addresses;

/**

* Constructs an empty AddressBook

*/

public AddressBook()

{

addresses = new ArrayList<Address>();

}

/**

* atparam st the name of a street

* atreturn a list with the names of each business with an address on that street

*/

public List<String> onStreet(String st)

{

// create an empty output list of names of business

List<String> businessName = new ArrayList<String>();

// loop over the list of addresses

for(int i=0;i<addresses.size();i++)

{

// if ith street of address = nm, add the name of the business to the output list

if(addresses.get(i).getStreet().equalsIgnoreCase(st))

businessName.add(addresses.get(i).getName());

}

return businessName; // return the list

}

/**

* Searches for an existing business with an identical address (street and number

* both match). Updates the record to an address with name nm, street st and number no.

* If no entry already exists adds a new address to the end of the list with these parameters.

*

* atparam nm the name of the business

* atparam st the street the business is on

* atparam no the street number of the business

* atreturn the index of where the business address is on the list

*/

public int newBusiness(String nm, String st, int no)

{

// loop over the list of addresses

for(int i=0;i<addresses.size();i++)

{

// if ith index addresses match the street and number of the input st and no

if((addresses.get(i).getStreet().equalsIgnoreCase(st)) && (addresses.get(i).getNumber() == no))

{

addresses.remove(i); // remove the ith address from list

addresses.add(i, new Address(nm,st,no)); // add a new address with the input name, street and number at ith index

return i; // return the index i

}

}

// if no address match, add the business at the end of the list

addresses.add(new Address(nm,st,no));

return addresses.size()-1; // return the last index

}

}

//end of AddressBook.java

5 0
3 years ago
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