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3 years ago

I need help is it a active scalene triangle yes or no?

Mathematics

1 answer:

mina [271]3 years ago

8 0

No it is not. that is a right scalene triangle. Acute triangle has three angles less than 90.

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What is 13 divided by 1/4?<br> Explain how you got your answer.

NeX [460]

Answer:

Step-by-step explanation:

13 divide 1/4 is the equivilent to 13 x 4

8 0

3 years ago

Read 2 more answers

Write in point slope form an equation of the line that passes through the given point and has the given slope: (0,1); m= 2

sergey [27]

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$\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond$

Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).

$\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond$

<u>Point-slope form</u>:-

$\sf{y-y_1=m(x-x_1)}$

Substitute 1 for y₁, 2 for m, and 0 for x₁:-

$\sf{y-1=2(x-0)}$

So we conclude that Option B is correct.

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3 0

2 years ago

The diagram below show the dimensions of a container of sand that is shaped like a rectangular prism . The container is filled u

monitta

Answer:

Its B

Step-by-step explanation:

6 0

3 years ago

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33 divide by 9537 plssss helpp me

klemol [59]

Answer:

1/289 or 0.03462749213

Step-by-step explanation:

33 / 9537

= 1/289 or 0.03462749213

4 0

3 years ago

Read 2 more answers

Unit 3 homework 6 Gina Wilson

Sonja [21]

Answer:

5) The equation of the straight line is 2 x - y + 1 =0

6) The equation of the straight line is x + y -5 =0

7) The equation of the straight line is 5 x + 6 y - 24 =0

8) The equation of the straight line is x - 4 y -4 =0

9) The equation of the parallel line is 3x + y -19 =0

Step-by-step explanation:

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,3) , ( -3,-5)

$m = \frac{-5-3 }{-3-1 } = \frac{-8}{-4} = 2$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 3 = 2 ( x - 1 )$

y = 2x - 2 +3

2 x - y + 1 =0

The equation of the straight line is 2 x - y + 1 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,4) , ( 6,-1)

$m = \frac{-1-(4) }{6-1 } = \frac{-5}{5} = -1$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 1 = -1 ( x - 4 )$

y - 1 = - x +4

The equation of the straight line is x + y -5 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-12 , 14) , ( 6,-1)

$m = \frac{-1-(14) }{6+12 } = \frac{-15}{18} = \frac{-5}{6}$

$y - 14 = \frac{-5}{6} ( x - (-12) )$

6( y - 14 ) = - 5 ( x +12 )

6 y - 84 = - 5x -60

5 x + 6 y -84 + 60 =0

5 x + 6 y - 24 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-4 , -2) , ( 4 , 0)

$m = \frac{0+2}{4 +4} = \frac{2}{8} = \frac{1}{4}$

$y - (-2) =\frac{1}{4} ( x - (-4) )$

4 ( y + 2) = x + 4

x - 4 y -4 =0

The equation of the line y = 3x + 6 is parallel to the line

3x + y + k =0 is passes through the point ( 4,7 )

⇒ 3x + y + k =0

⇒ 12 + 7 + k =0

⇒ k = -19

The equation of the parallel line is 3x + y -19 =0

4 0

3 years ago