The French club is holding a car wash fundraiser. They are going to charge $20 per car , and expect between 30 and 100 cars. Ide
2 answers:
Answer: Independent variable → number of cars
Dependent variable → money raised
Domain →30 to 100 cars
Range → $600 to $2000
Step-by-step explanation:
The independent variable here is the number of cars and the money raised by the club is dependent on the number of cars sold.
We know that the domain is the set of values of the independent variable from the least to maximum.
Since, they expect between 30 and 100 cars.
Therefore, the reasonable domain= 30 to 100 cars
The range is the set of values of the dependent variable, it is generally from the least to maximum.
The least amount they earn =
The maximum amount they earn =
Therefore, Range = $600 to $2000
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The degree is 3, the zeros are; 4, 2i, -2i and a point is (-48, 2)
For zeros; 2i, -2i <-- complex conjugates, always in pairs
= -4(i²=-1)
=5
=0
Therefore the equation is; a(
+5) <-- b value is zero
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)
For zeros; 2i, -2i <-- complex conjugates, always in pairs
= -4(i²=-1)
=5
=0
Therefore the equation is; a(
Rewrite the equation with all zeros;
a(x-4)(x²+5)=f(x) <-- put in coordinates of the points to find the value of x
a(2-4)(2²+5)=-48
a(2)(9)=-48
a=-48/18
a=-8/3
The final polynomial function is; (-8/3)(x-4)(x²+5)=f(x)
Hope I helped :)