Answer:
50% chance of passing english
40% chance of passing American History
30% chance of passing both classes
Step-by-step explanation:
Answer:
0.14
Step-by-step explanation:
From the question given above, the following data were obtained:
Grade A = 5
Grade B = 10
Grade C = 15
Grade D = 3
Grade F = 2
Sample space (S) = 35
Probability of getting grade A, P(A) =?
The probability that a student obtained a grade of A can be obtained as follow:
Probability of getting grade A, P(A) =
Event of A (nA) / Sample space, (nS)
P(A) = nA/nS
P(A) = 5/35
P(A) = 0.14
Thus, probability that a student obtained a grade of A is 0.14
Answer:
- 5
Step-by-step explanation:
"I am a negative integer greater than -6."
This eliminates any number that is less than -6, as well as any positive number.
0 > x > -6
"I am less than -2."
This narrows down the possible numbers to:
-5, -4, -3.
"I am not equal to -2 + (-1)"
-2 + - 1
-2 - 1
- 3
The number is not '-3'.
"I am not equal to 2 - 6."
2 - 6
- 4
The number is not -4.
Your number should be -5.
Hope this helps.
Given Information:
Mean SAT score = μ = 1500
Standard deviation of SAT score = σ = 3
00
Required Information:
Minimum score in the top 10% of this test that qualifies for the scholarship = ?
Answer:

Step-by-step explanation:
What is Normal Distribution?
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
We want to find out the minimum score that qualifies for the scholarship by scoring in the top 10% of this test.

The z-score corresponding to the probability of 0.90 is 1.28 (from the z-table)

Therefore, you need to score 1884 in order to qualify for the scholarship.
How to use z-table?
Step 1:
In the z-table, find the probability value of 0.90 and note down the value of the that row which is 1.2
Step 2:
Then look up at the top of z-table and note down the value of the that column which is 0.08
Step 3:
Finally, note down the intersection of step 1 and step 2 which is 1.28
Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense