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3 years ago

Are the lines y=4x+4 and y=-4x-2 parallel

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

7 0

Answer:

No these are not parallel

Step-by-step explanation:

Parallel lines have the same slope. 4 and -4 are not the same slope, which means they will intersect. A tool to check your answers such as this is Desmos. It really helps. Search Desmos graphing calculator. Hope this helps.

Alex Ar [27]3 years ago

6 0

Answer:

No they are not, they intersect at some point.

Step-by-step explanation:

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(x - 3)2 + (y + 2)2 = 4

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As a function this is x=3 y=3

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A framer sells 16 pounds or his small 48 pound potato crops what percent does he sell

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Answer:

Is it 32

Step-by-step explanation:

I think your suppose to subtract if you get it wrong i'm sorry

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There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o

Anastaziya [24]

P(B/A) is $\frac{5}{9}$ in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

P(B|A) is called the "Conditional Probability" of B given A
Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

replacement

- That means red is already occurred when green is happened,

so it is a "Conditional Probability" of green given red

P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

the first draw

∴ P(A) = P(red)

∵ P(red) = $\frac{3}{10}$

∴ P(A) = $\frac{3}{10}$

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = $\frac{5}{9}$

∴ P(B) = $\frac{5}{9}$

- Find P( A and B)

∴ P(A and B) = ( $\frac{3}{10}$ ) . ( $\frac{5}{9}$ )

∴ P(A and B) = $\frac{15}{90}$

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = $\frac{1}{6}$

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = $\frac{\frac{1}{6}}{\frac{3}{10}}$

- Simplify the fraction

∵ $\frac{1}{6}$ ÷ $\frac{3}{10}$ = $\frac{1}{6}$ × $\frac{10}{3}$ = $\frac{10}{18}$

- Divide up and down by 2

∴ P(B/A) = $\frac{5}{9}$

P(B/A) is $\frac{5}{9}$ in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

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3 years ago

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A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

3 years ago

A system of linear equations is graphed. Which ordered pair is the best estimate for the solution to the system? (12, 0) (1, 1)

GuDViN [60]

Line 1--------- >(0,2) (1,-1)
y=mx+b m=(-1-2)/(1-0)=-3
2=(-3)*(0)+b----- > b=2
y1=-3x+2

Line 2--------- >(0,-1) (2,2)
y=mx+b m=(2+1)/(2-0)=3/2
-1=(3/2)*(0)+b----- > b=-1
y2=(3/2)x-1

<span>using a graphic tool
see attached figure</span>

the best estimate solution for the system is <span>(1, 1)
because </span>is the only one within the range of the x axis (-5,5) and the y axis (-5,5)

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3 years ago

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