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almond37 [142]
3 years ago
14

PLEASE HELP NO SCAM ¼ (x+12) = 2

Mathematics
2 answers:
pashok25 [27]3 years ago
8 0
You put the answer as 2 already
kolbaska11 [484]3 years ago
3 0

Answer:

1/4 ( x + 12 ) = 2 : x = -4

Step-by-step explanation:

4 x 1/4 (x + 12 ) = 2 x 4

x + 12 = 8

x + 12 - 12= 8 - 12

x = -4

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Maggie was at a state fair and decided to but a sundae from an ice cream stand. The ice cream stand had four flavors of ice crea
I am Lyosha [343]

Total number of ice cream flavors = 4

(chocolate,vanilla,mint chip, coconut)

Number of toppings = 2

(hot fudge , caramel).

Different sundaes could Maggie create using one scoop of ice cream and one toppings = {(chocolate, hot fudge),(chocolate, caramel), (vanila, hot fudge),(vanilla,caramel), (mint chip, hot fudge), (mint chip,caramel), (coconut,hotfudge),(coconut,caramel) }= 8


6 0
4 years ago
Read 2 more answers
Evaluate g (x) = 4- 3x when x = -3, 0, and 5
Nataliya [291]

Answer:

13, 4, -11

Step-by-step explanation:

g(-3) = 4-3(-3) = 4+9 = 13

g(0) = 4-3(0) =4-0 = 4

g(5) = 4-3(5) = 4-15 = -11

7 0
3 years ago
What is a tenth of a decimal ?
trapecia [35]
One decimal place to the left decimal point is the place.
8 0
4 years ago
Order the values from<br> least to greatest:<br> | -4|,|3|, 0,-1
mrs_skeptik [129]

Answer: -4, -1, 0, 3

8 0
4 years ago
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A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
netineya [11]

Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

4 0
3 years ago
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