Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
B)blocks in 5th row=15+(5-1)(-2)
Step-by-step explanation:
We are given that
Number of block in bottom row=15
Each row has 2 fewer blocks than the previous row
We have to find the formula would you use to find the number of blocks in the 5th row.
Number of blocks in second row=15-2=
Number of blocks in third row=15-2-2=
Number of blocks in 4th row=
Number of blocks in 5th row=
Therefore, number of block in 5th row

This is required formula to find the number of blocks in the 5th row
Hence, option B is true.
B)blocks in 5th row=15+(5-1)(-2)
67 meters because if you use the triangle congruent method with the altitude at 65 degrees you should get the right answer
Answer:
16
Step-by-step explanation:
6(3)-2
16
The answer is 8
I hope this helps!