Given:
x = x1 + (x2 â’ x1)t,
y = y1 + (y2 ⒠y1)t where 0 ≤ t ≤ 1
vertices of triangle a(1, 1), b(5, 3), c(1, 7).
solution:
for getting AB apply points a and b in the above equations,
then x=1+4t , y=1+2t
for getting BC apply points b and c in the equations
then x=5-4t, y=3+4t
for getting CA apply points c and a in the equations
then x=1, y=7-6t
Answer:
equations for AB is x=1+4t , y=1+2t
equations for BC is x=5-4t, y=3+4t
equations for CA is x=1, y=7-6t
The distance formula between two points is :
The distance between vertices A(1, 4) and B(3, 6) is :
The distance between the vertices B(3, 6) and C(6, 3) is :
The area formula of a rectangle is length x width or AB x BC
The area will be :
The answer is A. 12 square units
Answer:
k=98
Step-by-step explanation:
<u>Let's solve your equation step-by-step.</u>
56=k−42
<u>Step 1: Flip the equation.</u>
k−42=56
<u>Step 2: Add 42 to both sides.</u>
k−42+42=56+42
k=98
I Hope This Helps If Not Then Im Srry....
Answer:
25
Step-by-step explanation:
I calculated it. I hope you pass! <3