Answer:
We need to shorten the time it takes to pick a customer order.
Explanation:
The operations management is the department in charge of supervising the operations related to the production and delivery of a product or a service of a company to its customers.
It would then them who would be in charge of reviewing the process or steps it takes to pick a customer order.
The other options are issues for the human resources department.
Answer:
The program is as follows:
#include <iostream>
#include <vector>
using namespace std;
int main(){
int n;
cout<<"Elements: ";
cin>>n;
vector <int>vectnum;
int numInp;
for (int i = 1; i <= n; i++){ cin>>numInp; vectnum.push_back(numInp); }
int big, secbig;
big = vectnum.at(0); secbig = vectnum.at(1);
if(vectnum.at(0)<vectnum.at(1)){ big = vectnum.at(1); secbig = vectnum.at(0); }
for (int i = 2; i< n ; i ++) {
if (vectnum.at(i) > big) {
secbig = big;;
big = vectnum.at(i);
}
else if (vectnum.at(i) > secbig && vectnum.at(i) != big) {
secbig = vectnum.at(i);
}
}
cout<<"Second Largest: "<<secbig<<endl;
int small, secsmall;
small = vectnum.at(1); secsmall = vectnum.at(0);
if(vectnum.at(0)<vectnum.at(1)){ small = vectnum.at(0); secsmall = vectnum.at(1); }
for(int i=0; i<n; i++) {
if(small>vectnum.at(i)) {
secsmall = small;
small = vectnum.at(i); }
else if(vectnum.at(i) < secsmall){
secsmall = vectnum.at(i); } }
cout<<"Second Smallest: "<<secsmall;
return 0;
}
Explanation:
See attachment for explanation
The Answer of the given question : D. Merging
Answer:
True
Explanation:
It's actually true because once a bidding page status changes to closed, it means that the timeframe for bidding has stopped, hence, no bidder will be able to bid again.
