The correct answer is resizing. If you're making a logo and creating wordart. you have to care about resizing because the art needs to be clearly visible and appealing no matter the size. If you place it in a box, you have to care that it doesn't go over the edges of the box or anything similar that might seem appalling.
Answer:Floating-point arithmetic is considered an esoteric subject by many people. This is rather surprising because floating-point is ubiquitous in computer systems. Almost every language has a floating-point datatype; computers from PCs to supercomputers have floating-point accelerators; most compilers will be called upon to compile floating-point algorithms from time to time; and virtually every operating system must respond to floating-point exceptions such as overflow. This paper presents a tutorial on those aspects of floating-point that have a direct impact on designers of computer systems. It begins with background on floating-point representation and rounding error, continues with a discussion of the IEEE floating-point standard, and concludes with numerous examples of how computer builders can better support floating-point.
Explanation:
Answer:
a.) Incoming packets can be placed in the buffer and played back without the jitter.
b.) Buffering would increase the latency because there would be a delay in time when the packets enter the buffer and the time is released.
Explanation:
Jitter is referred technically as a packet delay variations.
It is variation in the periodicity of periodic events or a signal from target or the true frequency.
Using the knowledge in computational language in C++ it is possible to write a code that asks the user to enter a number of gallons.
<h3>Writting the code:</h3>
<em>#include <iostream></em>
<em>using namespace std;</em>
<em>int main()</em>
<em>{</em>
<em> float gallons, cufeet;</em>
<em> cout << "\nEnter quantity in gallons : ";</em>
<em> cin >> gallons;</em>
<em> cufeet = gallons / 7.481;</em>
<em> cout << "Equivalent in cublic feet is " << cufeet << endl;</em>
<em> return 0;</em>
<em />
<em>}</em>
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