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7nadin3 [17]
3 years ago
9

FREE BRAINLIEST!! ill also answer questions that you have posted if you answer correctly!!!! (61pts)

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

Can I get the pdf?

Step-by-step explanation:

You might be interested in
What is the height of an equilateral triangle if the sides are 10
4vir4ik [10]

Answer:

The height of the equilateral triangle is 5\sqrt{3}\ units

Step-by-step explanation:

we know that

An equilateral triangle has three congruent sides, and three congruent angles that each measure 60 degrees

To find out the height of an equilateral triangle, apply the Pythagoras Theorem in the right triangle ABD

Remember that the height of an equilateral triangle bisects the base.

see the attached figure to better understand the problem

AB^2=AD^2+BD^2

substitute the given values

10^2=5^2+BD^2

Solve for BD

100=25+BD^2

BD^2=100-25

BD^2=75

BD=\sqrt{75}\ units

simplify

BD=5\sqrt{3}\ units`

therefore

The height of the equilateral triangle is 5\sqrt{3}\ units

7 0
4 years ago
Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
lukranit [14]

The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

S = (4,5)      

T = (5,9)

U=(3,8)

Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

8 0
3 years ago
Change the inequalities below to get 'y' by itself.(Please help me. I don't get how to do inequalities.)
astra-53 [7]

Answer:

y < x - 4

Step-by-step explanation:

First, move the x over to the other side by subtracting x from both sides. This will get you -y > -x + 4.

Divide both sides by -1 to get rid of the -1 in front of y. Since this is an inequality, dividing or multiplying by a negative number means that you have to flip the sign. We are dividing by a negative number, so flip > to <. The signs on both sides change to get y < x - 4.

6 0
3 years ago
Read 2 more answers
Read the following numbers and write them in expanded form 443 092 101<br>​
max2010maxim [7]
1) 400+40+3
2) 90+2
3) 100+1
7 0
3 years ago
PLEASEE HELPP I FORGOT HOW TO DO DIS !
elena55 [62]

The triangle has height 4.6 mm and its base has length 3.4 mm, so its area is

1/2 • 4.6 mm • 3.4 mm = 7.82 mm²

8 0
3 years ago
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