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NeTakaya
1 year ago
13

13. Find the range of the function on the graph below.

Mathematics
1 answer:
aliina [53]1 year ago
4 0

Range is ] -20 , -10 [

both points are disclude according to the empty circle

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Please help me with this :)<br>If fake answer, then will be reported!​
arsen [322]

Answer:

10 miles less

Step-by-step explanation:

To get the direct distance first, we use the pythagorean theorem. Distance from Ferris to Butte directly would be the hypotenuse. By solving for the hypotenuse, we have 25 miles. Now the distance used previously is 35 mile. Hence, it (35 - 25 = 10 ) miles less.

3 0
2 years ago
A rectangular prism has a length of 4 cm and a width of 5 cm.The volume of the prism is 200 cu cm .The height is unknown.Explain
Kaylis [27]

Answer:

Well just gonna explain kn the bottom but the answer is 10

Step-by-step explanation:

what you would have to do first is to jusy do 5x4 which is 20 then since you wanna find the volume yoi qould juat do 200 divide by 20 which is 10

3 0
3 years ago
Solve this quadratic form 3x-2x²=7 this is grade 9​
Pani-rosa [81]

Answer:

x

=

3

±

i

√

47

4

x=3±i474

Step-by-step explanation:

7 0
3 years ago
How much is 74 divided by 4
exis [7]

Answer:

18.5

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
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