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sergiy2304 [10]
2 years ago
14

Evaluate the expression for c = 3 and d = -1 cd2

Mathematics
2 answers:
asambeis [7]2 years ago
6 0

Answer: 3

Step-by-step explanation:

3(-1)^2

MrRa [10]2 years ago
4 0

Answer: 3

Step-by-step explanation:

hope this helps

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Suppose you invest $16000 at 9% interest and that it is compounded daily. How much will you have in 8 years?
kramer

Answer:

The amount after 8 years is $ 16,031.579

Step-by-step explanation:

Given as :

The Principal invested = $ 16000

The rate of interest compounded daily = 9 %

The time period = 8 years

Let The amount after 8 years = $ A

<u>From Compounded method </u>

Amount = Principal invested × (1+\dfrac{\textrm Rate}{365\times 100})^{365\times \textrm Time}

Or, Amount = 16000 × (1+\dfrac{\textrm 9}{365\times 100})^{365\times \textrm 8}

Or, Amount = 16000 × (1.0002465)^{8}

∴  Amount = $ 16,031.579

Hence The amount after 8 years is $ 16,031.579   Answer

4 0
3 years ago
PLS HELPP!!
Sphinxa [80]

Answer:

i dont know

Step-by-step explanation:

srry wish i could help you

5 0
2 years ago
Read 2 more answers
If a =5 and b=3 what is the value of the 2a-3b+3a
34kurt

Answer:

If a = 5 and b = 3, then that means 2a - 3b + 3a = 16

Step-by-step explanation:

2a - 3b + 3a

(2×5) - (3×3) + (3×5)

10 - 9 + 15 = 16

6 0
3 years ago
If sin =1/2then show that 3cos -4cos^3=0z
Katarina [22]

Step-by-step explanation:

ever coner should have a value.... for example sinA or cos$

please check the question again

7 0
2 years ago
Consider a data set containing the following values: 70 65 71 78 89 68 50 75 The mean of the preceding values is 70.75. The devi
Leokris [45]

Answer:

If this is the sample data, the sample variance is 125.07 and the sample standard deviation is 11.18

If this is a population data, the population variance is 109.44 and the population standard deviation is 10.46

Step-by-step explanation:

We are given the following data-set:

70, 65, 71, 78, 89, 68, 50, 75

Deviations from the mean

–0.75, –5.75 , 0.25, 7.25, 18.25, –2.75, –20.75, 4.2

Sample size, n = 8

Sample:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

s = \sqrt{\dfrac{875.5}{7}} = 11.18

\text{ Sample variance} = s^2 = 125.07

Population:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.

Sum of squares of differences =

0.5625 + 33.0625 + 0.0625 + 52.5625 + 333.0625 + 7.5625 + 430.5625 + 18.0625 = 875.5

\sigma = \sqrt{\dfrac{875.5}{8}} = 10.46

\text{ Population variance} = \sigma^2 = 109.44

7 0
3 years ago
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