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Alexxandr [17]
3 years ago
5

6 less than the quotient of z divided by 3

Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

z/3 - 6

Step-by-step explanation:

just wrote out what the words said in math!

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Which pair are equal trig values? A) tan 45° and sin 45° Eliminate B) sin 40° and sin 50° C) sin 36° and cos 54° D) cos 65° and
ira [324]

Answer:

C

Step-by-step explanation:

note that sin x = cos(90 - x ) ← Cofunction identity

If x = 36 then 90 - x = 90 - 36 = 54

Hence sin 36° = cos 54° → C


3 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
If y varies inversely with the square of r, what is the constant of proportionality when y - 10 and 1 = 5?
Anvisha [2.4K]

<em><u>Question:</u></em>

If y varies inversely with the square of r, what is the constant of proportionality when y =10 and r = 5?

<em><u>Answer:</u></em>

The constant of proportionality is 250

<em><u>Solution:</u></em>

Given that,

y varies inversely with the square of r

Which means,

y \propto \frac{1}{r^2}\\\\y = k \times \frac{1}{r^2}

Where, "k" is constant of proportionality

Subtitute y = 10 and r = 5

10 = k \times \frac{1}{5^2}\\\\10 = k \times \frac{1}{25}\\\\k = 10 \times 25\\\\k = 250

Thus the constant of proportionality is 250

6 0
3 years ago
What's the average rate of change?<br> f(x) over 4&lt;=x&lt;=7
N76 [4]

Answer:

i dont know

Step-by-step explanation:

XD like am i supposed to jknow that?

8 0
3 years ago
What is 3.56 times 82 equals
Pavlova-9 [17]
You would multiply 3.56 by 82 and get 291.92
7 0
4 years ago
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