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Ivanshal [37]
3 years ago
7

BRAINLIEST asap solve the problem.​

Mathematics
1 answer:
podryga [215]3 years ago
3 0
S=27

Use the equation given and substitute 53.45 for c and 63 for r, like indicated in the problem. Then solve and get s=27.

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a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

E = 6500 - 1500

E = 5000

<em>Hence, there are 5000kwh left after 30 days</em>

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