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matrenka [14]
3 years ago
15

What are the domain and range of the function below?

Mathematics
2 answers:
Natalka [10]3 years ago
8 0

Answer:

Domain is the set of all real numbers

Range is the set of all real numbers.

Step-by-step explanation:

Given a graph with curve which has y intercept -5, and x intercept 5.

The graph is  continuous at all points of x and y

We find that the graph is a straight line with positive slope of the form

x/5 +y/-5=1

Or x-y =5

The graph is defined for all values of x and y.

The domain is the set of values x can take  

In the graph horizontal axis is x axis.

Hence from the graph we see that x can take values from -infinity to + infinity

Hence domain is x = R

For range, we consider the values of y as per graph.

WE find that y is  taking values in the interval (-infinity, infinity)

Hence Range =R

Pie3 years ago
4 0

Answer:

The dude above is right . . . all real values/numbers = -infinity to infinity

Step-by-step explanation:

This is literally the definition of infinity: all numbers, so negative infinity to infinity is all the possible real numbers. Please rate the guy above 5 stars this dude is the real champ. Your answer is D) (negative infinity to infinity) as range and domain.

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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
I will mark you brainliest!!
lakkis [162]

Answer:

Alternate-exterior angles theorem.

Step-by-step explanation:

Two parallel lines are cut by a transversal, and if there are a pair of congruent angles that are outside of the parallel lines, and on opposite sides of the transversal, you will have the alternate-exterior angles theorem.

4 0
3 years ago
Thea would like to leave a 15% tip.<br> Her bill was $5.40. How much should<br> she leave?
iogann1982 [59]

Answer:

(5.40/100)*115 = 6.21 - 5.40 = 0.81 cents

Step-by-step explanation:

8 0
3 years ago
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