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Kobotan [32]
3 years ago
8

HELP MATH WORD PROBLEM.

Mathematics
1 answer:
katrin [286]3 years ago
3 0
The cost per chair is $2 and the cost per table $6
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Ahmad wants to practice free-throws. He estimates the distance from the free-throw Line to the hoop and marks it with chalk. Ahm
const2013 [10]

Answer: 10%

Step-by-step explanation:

The difference between his estimated and actual distance is 15 - 13.5 = 1.5

The percentage of error is the difference divided by the actual value.

1.5÷15 = 0.10

Converted to a percentage, it is 10%

4 0
3 years ago
Read 2 more answers
Consider the function. What is the y-intercept of f–1(x)? –16 –12
Mekhanik [1.2K]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write clear questions in order to get good and exact answers. Here, I'll assume the function as:

f(x)=x^2+2x-16

The y-intercept of a function is the point at which the graph of the function touches the y-axis. This occurs when we set x=0. In other words, we define the y-intercept (let's call it b as:

b=f(0)

Setting x=0 in our function we have:

b=f(0)=(0)^2+2(0)-16 \\ \\ \boxed{b=f(0)=-16}

So <em>in this context the y-intercept is -16</em>

7 0
3 years ago
Definition of 8x_ coefficient
den301095 [7]
The answer is I. K. D.
6 0
2 years ago
I really need help with 1 and 2 please help me I begg you
Lera25 [3.4K]
1.) So 1/5 of a relay, or r, is 3/4 of a mile.
1/5r = 3/4
Multiply 5 on both sides of the equation.

r = 15/4

The relay was 15/4 of a mile or 3 3/4 of a mile.

2.) No, it is not because the sum of the digits are not divisible by 3.

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
29. Find the height of the trapezoid. Use this height to find the area. (A =
harkovskaia [24]

Answer:

<em>The area of the trapezium is 168</em>

Step-by-step explanation:

<u>Area of a Trapezoid</u>

Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:

\displaystyle A=\frac{b_1+b_2}{2}h

The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:

10^2=EC^2+BC^2

The side BC can be found as half the difference of the bases:

BC=\frac{27-15}{2}=6

Solving for EC:

EC^2=10^2-6^2=100-36=64

EC=\sqrt{64}=8

Now we have the height, calculate the area:

\displaystyle A=\frac{15+27}{2}*8

\displaystyle A=\frac{42}{2}*8

A = 168

The area of the trapezium is 168

5 0
3 years ago
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