Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer: x=75
Explanation:
x+10+x+20=180
combine like terms
2x+30=180
subtract 30 from each side
2x=150
divide each side by 2
x=75
A because 750 times 12 because there is 12 months in a year. You get 9000
As the three longitudinal lines are parallel:
angle 4 = 5 = 6 = 82 degree (corresponding angles) = 9 = 8 = 7 = 82 degrees (vertical angles)
and
angle 11 = 180-82= 98 degrees (linear pair)
so:
angle 10 = 11 = 12 = 98 degrees (corresponding angles) = 3 = 2 = 1 = 98 degrees (vertical angles)
.
hope you got it
Answer:
Step-by-step explanation:
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