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Kipish [7]
3 years ago
11

A 1948 study in Biometrika investigated the effects of several different diets on the weight of chickens. In this study, chicken

s were randomly assigned to one of several different groups, and each group of chickens received a different type of feed. The data provided represent a subset of data from this study and show the weights (in grams) of chickens receiving the sunflower, meatmeal, soybean, and casein feeds.
Use software to conduct an analysis of variance (ANOVA) ????F‑test to test the claim that the mean weights of chickens receiving sunflower, meatmeal, soybean, and casein are equal. What are the ????F‑statistic and pp‑value for this test? Please round your ????F‑statistic to the nearest two decimal places and your pp‑value to the nearest five decimal places.
1. ????F‑statistic :
2. pp‑value :
Based on the pp‑value for this ANOVA ????F‑test, select the correct conclusion at the ????=0.05α=0.05 level.
a. Since the pp‑value is greater than ????=0.05α=0.05, there is little evidence of a difference in the mean weights of chickens receiving the sunflower, meatmeal, soybean, and casein feeds.
b. Since the pp‑value is less than ????=0.05α=0.05, there is significant evidence of a difference in the mean weights of chickens receiving the sunflower, meatmeal, soybean, and casein feeds.
c. Since the pp‑value is less than ????=0.05α=0.05, there is little evidence of a difference in the mean weights of chickens receiving the sunflower, meatmeal, soybean, and casein feeds.
d. Since the pp‑value is greater than ????=0.05α=0.05, there is significant evidence of a difference in the mean weights of chickens receiving the sunflower, meatmeal, soybean, and casein feeds.
weight feed
368 1
390 1
379 1
260 1
404 1
318 1
352 1
359 1
216 1
222 1
283 1
332 1
325 2
257 2
303 2
315 2
380 2
153 2
263 2
242 2
206 2
344 2
258 2
243 3
230 3
248 3
327 3
329 3
250 3
193 3
271 3
316 3
267 3
199 3
171 3
158 3
248 3
423 4
340 4
392 4
339 4
341 4
226 4
320 4
295 4
334 4
322 4
297 4
318 4
Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

hope this helps!! ^.^ -

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Using the midpoint formula, the coordinates of endpoint H are (4, -6).

<h3>The Midpoint Formula</h3>

The midpoint formula is given as: (x_m, y_m) = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} )

<em>Where</em>,

(x_m, y_m) = coordinates of the midpoint

(x_1, y_1) = coordinates of the first point

(x_2, y_2) = coordinates of the second point

Given the following:

(x_m, y_m) = M( 6,-4)

(x_1, y_1) = G(8,-2)

(x_2, y_2) = H(?, ?)

Plug in the values into the midpoint formula

M(6, -4) = (\frac{8 + x_2}{2}, \frac{-2 + y_2}{2} )

Solve for the x-coordinate and y-coordinate separately

6 = \frac{8 + x_2}{2}

  • Multiply both sides

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Therefore, using the midpoint formula, the coordinates of endpoint H are (4, -6).

Learn more about midpoint formula on:

brainly.com/question/13115533

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2 years ago
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Answer:

y = -2x - 1

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So equation is now y = -2x + b

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y = -2x + b

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3 years ago
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Answer:

the answer is d

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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