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GREYUIT [131]
2 years ago
6

Which is the best estimate of the product of the fractions? StartFraction 4 Over 7 EndFraction times StartFraction 8 Over 9 EndF

raction times StartFraction 14 Over 15 EndFraction
Mathematics
1 answer:
Lapatulllka [165]2 years ago
8 0

Answer:

Product = \dfrac{64}{135}

Step-by-step explanation:

The expression is as follows :

\dfrac{4}{7}\times \dfrac{8}{9}\times \dfrac{14}{15}

We need to find the product of the above expression

As 7 × 2 = 14

So, it will become :

4\times \dfrac{8}{9}\times \dfrac{2}{15}\\\\=\dfrac{4\times 8\times 2}{9\times 15}\\\\=\dfrac{64}{135}

So, the product of the given fractions is \dfrac{64}{135}.

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Find f(-2) for the following function. <br><br>f(x)=3.6x-2​
butalik [34]

Answer:

f(- 2) = - 9.2

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x) , that is

f(- 2) = 3.6(- 2) - 2 = - 7.2 - 2 = - 9.2

4 0
3 years ago
Corinne has a job selling magazines. She earns $7.50 per hour plus 20% of the total amount of her sales. She also gets an allowa
maw [93]
PART A
Coefficient
Coefficient h is 7.50
Coefficient s is 0.20

Variable
h and s

Constant
40

PART B
7.50h + 0.20s + 40
= 7.50(25) + 0.20(300) + 40
= 187.5 + 60 + 40
= 287.5
She earns $287.5

PART C
Yes, the coefficient of h would change to 9, the rests are still the same. Because she's no longer receive 7.50 per hour, and start earning 9 per hour, so the coefficient should change.
The expression would be
9h + 0.20s + 40
4 0
3 years ago
A 150-unit apartment complex is infested with rats. The apartment caretaker checked 9 units and found the following number of ra
MA_775_DIABLO [31]
{2, 5, 3, 1, 0, 3, 7, 2, 2} is the data set. We can find this by finding <span>relative frequency of 3 = 2/9 = 0.22 and then 150 times .22 = 33 units</span>
8 0
3 years ago
First question, thanks. I believe there should be 3 answers
zysi [14]

Given: The following functions

A)cos^2\theta=sin^2\theta-1B)sin\theta=\frac{1}{csc\theta}\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}

B

\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}

C

\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}

D

\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}

E

\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}

Hence, the following are identities

\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

The marked are the trigonometric identities

3 0
1 year ago
What's (7 x 100) + (4 x /100) + (8 x 1/1000) in standard form?
IceJOKER [234]

Answer:

(7*100) can be written as 7*10^2

4 * / 100 i don’t know

if it was 4 * 100 then it’s 4*10^2

if it was divided then it’s 4*10^-2

8* 1/1000 = 8/1000 = 8*10^-3

add together to get 1.100008 * 10^3 (if it was 4*100)

or 7.00048 * 10^2 ( if it was 4/100)

7 0
3 years ago
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