Answer:
Using Matlab code for Fourier series to calculate for the function, see the attached
Step-by-step explanation:
Go through the picture step by step.
Let's solve for x.
x
+
4
y
=
(
14
)
(
3
)
x
+
7
y
Step 1: Add -42x to both sides.
x
+
4
y
+
−
42
x
=
42
x
+
7
y
+
−
42
x
−
41
x
+
4
y
=
7
y
Step 2: Add -4y to both sides.
−
41
x
+
4
y
+
−
4
y
=
7
y
+
−
4
y
−
41
x
=
3
y
Step 3: Divide both sides by -41.
−
41
x
−
41
=
3
y
−
41
x
=
−
3
41
y
Answer:
x
=
−
3
41
y
Answer:bhbehrf
Step-by-step explanation:
Answer:
If I could get the values of a, b, and c i'd solve the whole thing.
Step-by-step explanation:
8a + 9b divided by 8a - 9b =
9b + 5c divided by 18b - 10c =
5c + 8a divided by 15c - 24a
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft