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Vikentia [17]
3 years ago
10

Please helpppppp

Mathematics
1 answer:
melomori [17]3 years ago
6 0

Given Information:

Years = t = 35

Semi-annual deposits = P = $2,000

Compounding semi-annually  = n = 2

Interest rate = i = 6.5%  

Required Information

Accumulated amount  = A = ?

Answer:

Accumulated amount  = $515,827

Step-by-step explanation:

The future value of amount earned over period of 35 years and interest rate 6.5% with semi-annual deposits is given by

FV = PMT * ((1 + i/n)^nt - 1)/(i/n))

Where  

n = 2

i = 0.065

t = 35

FV = 2000*((1 + 0.065/2)^2*35 - 1)/(0.065/2))

FV = 2,000*(257.91)

FV ≈ $515,827

Therefore, Anthony will have an amount of $515,827 when he retires in 35 years.

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arc AC = 111°

Step-by-step explanation:

∠APC is a central angle, so arc AC is equal to the measure of ∠APC.

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2 years ago
Given two similar triangles, how does one use proportions to find the lengths of one of the sides of one of the triangles? Answe
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➷ As they are similar triangles, there will be a scale factor between them. You may be given one pair of values on the triangle. Divide the larger value by the smaller value in order to find the scale factor between the triangles. For example, if the larger triangle has a length of 6cm and the smaller triangle has a length of 3cm, the scale factor would be 2. You would then multiply the given side by the scale factor to get the length.

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3 years ago
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3 years ago
Use properties of addition and subtraction to evaluate the expression. −24−8−26 Enter your answer in the comments below.
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Use the following table for questions 11-13.A baseball manager believes a linear relationship exists between the number of Home
slamgirl [31]

The regression equation of Y on X is given by the following formula:

Y-\bar{Y}=b_{yx}(X-\bar{X})

Where byx is given by the formula:

b_{yx}=\frac{N\sum^{}_{}XY-\sum^{}_{}X\sum^{}_{}Y}{N\sum^{}_{}X^2-(\sum^{}_{}X)^2}

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.

The table of values is:

The values we need to know are on the following table:

By replacing the known values in the formula we obtain:

\begin{gathered} b_{yx}=\frac{8\cdot26125-167\cdot995}{8\cdot4649-(167)^2} \\ b_{yx}=\frac{209000-166165}{37192-27889} \\ b_{yx}=\frac{42835}{9303} \\ b_{yx}=4.6 \end{gathered}

Now, the average of X and Y is the sum divided by N, then:

\begin{gathered} \bar{X}=\frac{167}{8}=20.87 \\ \bar{Y}=\frac{995}{8}=124.37 \end{gathered}

Replace these values in the formula and find the regression equation as follows:

\begin{gathered} Y-124.37=4.6(X-20.87) \\ Y-124.37=4.6X-4.6\cdot20.87 \\ Y=4.6X-96.11+124.37 \\ Y=4.6X+28.26 \end{gathered}

The answer is a) y=4.6x+28.26

7 0
1 year ago
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