Pls help no wrong answer pls pls pls

The box plots show the math scores of students in two different classes. Based on the box plots, which statement is correct?

Allisa [31]

Based on the box plots, the statement which is correct is that: A. The median score of Class A is greater than the median score of Class B.

<h3>What is a box and whisker plot?</h3>

In Mathematics, a box plot is also referred to as box and whisker plot and it can be defined as a type of chart that can be used to graphically or visually represent the five-number summary of a data set with respect to locality, skewness, and spread.

Additionally, the five-number summary of any box plot (box and whisker plot) include the following:

Minimum
First quartile
Median
Third quartile
Maximum

By critically observing the box plot (box and whisker plot) which represent the math scores of students in in two different classes, we can reasonably and logically deduce the following median scores;

Median score of class A = 80

Median score of class B = 75

Therefore, a median score of 80 in Class A is greater than the median score of 75 in Class B.

Read more on box plots here: brainly.com/question/14277132

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6 0

1 year ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

MArishka [77]

Answer:

all work is shown and pictured

8 0

3 years ago

Express 4x^2 − 12x in the form (2x + a)^2 + b.

gladu [14]

Answer: $(2x-3)^2-9\\$

a=-3

b=-9

Step-by-step explanation:

$4x^2-12x=(2x)^2-2*2x*3+9-9\\=(2x-3)^2-9\\$

8 0

3 years ago

What is the slope formula of (4,2) and (7, 6.5)

Lady_Fox [76]

Suppose the given coordinates are represented as,

$\begin{gathered} (x_1,y_1)=(4,2) \\ (x_2,y_2)=(7,6.5) \end{gathered}$

Then, the formula for slope can be expressed as,

$\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{6.5-2}{7-4} \end{gathered}$

Solving it,

$m=\frac{4.5}{3}=1.5$

The slope is 1.5.

The formula of (10, 8) anjd (-5,8) is

$m=\frac{8-8}{-5-10}$

3 0

1 year ago

A certain three-cylinder combination lock has 60 numbers on it. To open it, you turn to a number on the first cylinder, then

statuscvo [17]

Answer:

(a) The number of different lock combinations is 216,000.

(b) The probability of getting the correct combination in the first try is $\frac{1}{216000}$ .

Step-by-step explanation:

The lock has three-cylinder combinations with 60 numbers on each cylinder.

The procedure of the opening lock is to turn to a number on the first cylinder, then to a second number on the second cylinder, and then to a third number on the third cylinder.

The numbers can be repeated.

(a)

There are three cylinder combinations on the lock, each with 60 numbers.

It is provided that repetitions are allowed.

Then each cylinder can take any of the 60 numbers.

So there are 60 options for the first cylinder.

There are 60 options for the second cylinder.

And there are 60 options for the third cylinder.

So the total number of possible combinations is:

Total number of combinations = 60 × 60 × 60 = 216000.

Thus, the number of different lock combinations is 216,000.

(b)

The events of getting a correct combinations of the three-cylinder combination lock implies that all the three cylinder are set at the correct numbers.

Each cylinder has 60 numbers.

This implies that there are 60 possible ways to get a correct number for the first cylinder.

The probability of getting the correct number for the first cylinder is:

P (Number on 1st cylinder is correct) = $\frac{1}{60}$ .

Similarly for the second cylinder the probability of getting the correct number is:

P (Number on 2nd cylinder is correct) = $\frac{1}{60}$ .

And similarly for the third cylinder the probability of getting the correct number is:

P (Number on 3rd cylinder is correct) = $\frac{1}{60}$ .

So the probability of getting the correct combination in the first try is:

P (Correct combination in the 1st try) = $\frac{1}{60}\times \frac{1}{60}\times \frac{1}{60}=\frac{1}{216000}$ .

Thus, the probability of getting the correct combination in the first try is $\frac{1}{216000}$ .

7 0

3 years ago