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4 years ago

What is 143x+4=12 please help

Mathematics

2 answers:

garik1379 [7]4 years ago

6 0

Isolate the variable by dividing each side by factors that don’t contain variables.

Answer: 8/143

Vika [28.1K]4 years ago

3 0

X= 8/143

First you need to move the constant to the right of the equals sign. = 143x=12-4

Second you need to calculate it when the constant is on the right side. = 143x=8

lastly you need to divide both sides. (both sides divided by what ever number doesn’t have a variable next to it so that would be the right side on this question)

Hope this helps !!
Good luck doing school tomorrow you should go to sleep soon !!

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The Pew Research Center has conducted extensive research on the young adult population (Pew Research website, November 6, 2012).

Rudik [331]

Answer:

a) $0.93 - 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.908$

$0.93 + 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.952$

The 95% confidence interval would be given by (0.908;0.0.952)

b) $0.21 - 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.163$

$0.21 + 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.257$

The 99% confidence interval would be given by (0.163;0.0.257)

c) The margin of error for part a is:

$ME= 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.0224$

And for part b is:

$ME=2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.0470$

So then the margin of error is larger for part b.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.93 - 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.908$

$0.93 + 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.952$

The 95% confidence interval would be given by (0.908;0.0.952)

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.21 - 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.163$

$0.21 + 2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.257$

The 99% confidence interval would be given by (0.163;0.0.257)

Part c

The margin of error for part a is:

$ME= 1.96\sqrt{\frac{0.93(1-0.93)}{500}}=0.0224$

And for part b is:

$ME=2.58\sqrt{\frac{0.21(1-0.21)}{500}}=0.0470$

So then the margin of error is larger for part b.

7 0

3 years ago

WILL MARK BRAINLEST PLEASE HELP!!!!!!!!!

Harrizon [31]

Answer is 3.

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3 years ago

A company tests two new products to make sure they last for more than a year. Product 1 had 950 out of 1,000 test items last for

zheka24 [161]

Answer:

product one; it has a higher success rate

Step-by-step explanation:

to find out which has a higher rate of success we can find out their percentage of success

we can divide their success amounts by test amounts

950 / 1000 = 95/100 = 95%

150/200 = 75/100 = 75%

product 1 has a higher success rate

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3 years ago

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barxatty [35]

Answer:

Restating the question clearly:

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Answer:

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Step-by-step explanation:

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3 years ago

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Goryan [66]

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3 years ago