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algol [13]
3 years ago
15

How to factor 9X^3-27

Mathematics
1 answer:
azamat3 years ago
4 0
You will find teh GCF of that this will give you 9(x3-3) now you can fator it teh factors of these can be (x2+1) and (x-3)
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a _{n} = a + (n - 1) \times d \\ 67 = 13 + (n - 1) \times 3 \\ 67 = 13 + 3n - 3 \\ 67 - 13  + 3 = 3n \\ 57 = 3n \\ 3n = 57 \\  \\ n =  \frac{57}{3}  \\  \\ n = 19

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