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MrRa [10]
2 years ago
15

Which statements are true about the ordered pair(−1,−4) and the system of equations?

Mathematics
2 answers:
ElenaW [278]2 years ago
7 0
The correct answer is A
UNO [17]2 years ago
6 0

the correct answer is A

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Cd has an endpoint at (2, -1) and a midpoint at (8, 3). which measure is closest to the length of cd
stepladder [879]

Answer:

4\sqrt{13}

Step-by-step explanation:

The length of CD will be twice the distance from the midpoint to the endpoint

To calculate the length use the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (2, - 1) and (x₂, y₂ ) = (8, 3)

d = 2 × \sqrt{(8-2)^2+(3+1)^2}

  = 2 × \sqrt{6^2+4^2}

  = 2 × \sqrt{52}

  = 2 × \sqrt{4(13)}

  = 2 × 2\sqrt{13} = 4\sqrt{13} ← exact length

8 0
3 years ago
Please write out the problem on paper
skad [1K]
Your answer will be n5
7 0
3 years ago
100x²7<br> Quadratic equation
grin007 [14]
Hope the answer I gave you helps!!!
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3 0
3 years ago
Write an expression to show k less than 3.5
Natalija [7]
Answer: k < 3.5
explanation: < means less than and > means more than and = means equal to so k < (less than) 3.5
5 0
3 years ago
Consider the following set of equations, where s, s0, x and r have units of length, t has units of time, v has units of velocity
Anna11 [10]

Answer:

5

Step-by-step explanation:

For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.

Also, two physically quantities can only be added or subtracted only when their dimension are same.

here all option are dimensionally correct except the 5th option where

dimension of t= [T] whereas dimension of a/v is \frac{LT^{-2}}{LT^{-1}}

= T^{-1}

since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.

8 0
3 years ago
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