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2 years ago

Show your work” below and solve the given equation for x showing all your steps.

Mathematics

1 answer:

mixas84 [53]2 years ago

4 0

Answer:

x=-13

Step-by-step explanation:

21-3.5x+14=7-7.5x-24

21+14-3.5x=7-24-7.5x

35-3.5x=-17-7.5x

35+17=3.5x-7.5x

52=-4x

-4. -4

x=-13

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Without graphing, is the system independent, dependent, inconsistent? {12x=3y=12 y=-4x+5

Alla [95]

Okay so you out them into the form of y=mx+b. since equation 2 is already like that you need to do it to equation 1. which is y=-4x+4. graph both equations. if it has a solution (1 point where the two lines meet) it is consistantly and independent. if they are parallel lines and the solution is 0 the system is inconsistent and the lines are dependent. if it's the same line they are consistent and dependent. the line is not the same since the y intercept is different. the slope is the same though which tells us its parallel. so the system has a solution of 0 and is inconsistent and the lines are independent.

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3 years ago

SOMEONE HELP ME FIND THE Y PLEASE ASAP

Evgesh-ka [11]

Answer:

(Down Below)

Step-by-step explanation:

Plug in the value of x in the left column for all the values in the equation. I will do a couple for you.

Since -4 is the value of x, substitute it into the equation for x.

$y= -4-5=-9$

-1

$y=-1-5=-6$

$y=0-5=-5$

You can do the rest. You got this! Comment if you need more help!

3 0

2 years ago

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The equation y = 0.25x + 50 gives the cost y of renting a car if the car is driven x miles

iogann1982 [59]

C. $112.50

y=0.25x+50

x = 250 miles

0.25*250=62.50

62.50+50= $112.50

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3 years ago

Read 2 more answers

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Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Consider the line y=-5/9x+6

Arlecino [84]

Answer:

See below in bold.

Step-by-step explanation:

Use the point-slope form of a straight line

y - y1 = m(x - x1)

Here m = -5/9 , x1 = 9 and y1 = -3:, so

y - -3 = -5/9(x - 9)

y + 3 = -5/9x + 5

y = -5/9x + 2 is the equation parallel to the given line.

The line perpendicular to the given line will have a slope of - 1 / -5/9

= 9/5 so its equation is

y + 3 = 9/5(x - 9)

y = 9/5x - 81/5 - 3

y = 9/5x - 96/5 .

4 0

2 years ago